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Focal Length of Spherical Mirrors

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Estimated time: 7 minutes
CBSE: Class 12

Introduction

When a parallel beam of paraxial light strikes a spherical mirror, the reflected rays do not scatter randomly — they either converge to a single point (concave mirror) or appear to diverge from a single point (convex mirror). This special point, and the distance to it from the mirror surface, defines what we call the focal length.

Focal length is arguably the most important single parameter describing a spherical mirror. The mirror formula, magnification, and image position — all depend on it. The key result proved in this module is:

f = \[\frac {R}{2}\]

That is, the focal length of any spherical mirror equals exactly half its radius of curvature.

CBSE: Class 12

Definition: Principal Focus

The point F on the principal axis where a parallel paraxial beam of light converges (or appears to diverge from) after reflection is called the Principal Focus of the mirror.

CBSE: Class 12

Definition: Focal Plane

The plane perpendicular to the principal axis passing through the principal focus F is called the Focal Plane of the mirror.

CBSE: Class 12

Definition: Focal Length

The distance between the Principal Focus F and the Pole P of the mirror is called the Focal Length, denoted by f.

f = \[\overline {PF}\]

CBSE: Class 12

Derivation of f = R/2

Setup

Consider a concave spherical mirror with:

  • P = Pole of the mirror
  • C = Centre of curvature (radius of curvature = R = CP)
  • F = Principal focus
  • A ray parallel to the principal axis strikes the mirror at point M

Step 1: Identify the normal at M

The normal at any point on a spherical mirror passes through the centre of curvature C. Therefore, CM is the normal at M.

Step 2: Apply the law of reflection

Let θ = angle of incidence (between incident ray and CM).
By the law of reflection, the angle of reflection = θ.

Therefore:

  • ∠MCP = θ (angle at C in triangle MCF)
  • ∠MFP = 2θ (exterior angle of triangle MCF)ncert

Step 3: Set up trigonometric relations

Drop a perpendicular MD from M to the principal axis. Then:

  • tan ⁡θ = \[\frac {MD}{CD}\] and tan ⁡2θ = \[\frac {MD}{FD}\]

Step 4: Apply small-angle (paraxial) approximation

For paraxial rays, θ is very small. Hence:

  • tan ⁡θ ≈ θ and tan ⁡2θ ≈ 2θ

Substituting:

  • \[\frac {MD}{FD}\] = 2 ⋅ \[\frac {MD}{CD}\]
  • FD = \[\frac {CD}{2}\]

Step 5: Apply paraxial approximation to distances

For paraxial rays, M is very close to P, so D is very close to P:

  • FD ≈ FP = f and CD ≈ CP = R

Step 6: Final result

Substituting into equation (1):

  • f = \[\frac {R}{2}\]

This result holds for both concave and convex mirrors.

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