English

Obtain the Expression for Mutual Inductance of a Pair of Long Coaxial Solenoids - Physics

Advertisements
Advertisements

Question

Obtain the expression for mutual inductance of a pair of long coaxial solenoids each of length l and radii r1 and r2 (r2 >> r1). Total number of turns in the two solenoids are N1 and N2, respectively.

Advertisements

Solution

Suppose a current i is passed through the inner solenoid S1.

A magnetic field B=μ0n1i is produced inside S1 , whereas the field outside it is zero.

The flux through each turn S2 is Bπr12=μ0n1iπr12

The total flux through all the turns in a length l of S2 is

ϕ=(μ0n1iπr12)n2l=(μ0n1n2πr12l)i

M=μ0n1n2πr12l

shaalaa.com
  Is there an error in this question or solution?
2016-2017 (March) Delhi Set 1

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

Use this law to obtain the expression for the magnetic field inside an air cored toroid of average radius 'r', having 'n' turns per unit length and carrying a steady current I.


Two long coaxial insulated solenoids, S1 and S2 of equal lengths are wound one over the other as shown in the figure. A steady current "I" flow thought the inner solenoid S1 to the other end B, which is connected to the outer solenoid S2 through which the same current "I" flows in the opposite direction so as to come out at end A. If n1 and n2 are the number of turns per unit length, find the magnitude and direction of the net magnetic field at a point (i) inside on the axis and (ii) outside the combined system


Define the term self-inductance of a solenoid.


A wire AB is carrying a steady current of 12 A and is lying on the table. Another wire CD carrying 5 A is held directly above AB at a height of 1 mm. Find the mass per unit length of the wire CD so that it remains suspended at its position when left free. Give the direction of the current flowing in CD with respect to that in AB. [Take the value of g = 10 ms−2]


Define mutual inductance between two long coaxial solenoids. Find out the expression for the mutual inductance of inner solenoid of length having the radius r1 and the number of turns n1 per unit length due to the second outer solenoid of same length and r2 number of turns per unit length.


 Draw and compare the pattern of the magnetic field lines in the two cases ?


The magnetic field inside a tightly wound, long solenoid is B = µ0 ni. It suggests that the field does not depend on the total length of the solenoid, and hence if we add more loops at the ends of a solenoid the field should not increase. Explain qualitatively why the extra-added loops do not have a considerable effect on the field inside the solenoid.  


A long solenoid of radius 2 cm has 100 turns/cm and carries a current of 5 A. A coil of radius 1 cm having 100 turns and a total resistance of 20 Ω is placed inside the solenoid coaxially. The coil is connected to a galvanometer. If the current in the solenoid is reversed in direction, find the charge flown through the galvanometer.


A tightly-wound, long solenoid carries a current of 2.00 A. An electron is found to execute a uniform circular motion inside the solenoid with a frequency of 1.00 × 108 rev s−1. Find the number of turns per metre in the solenoid. 


A capacitor of capacitance 100 µF is connected to a battery of 20 volts for a long time and then disconnected from it. It is now connected across a long solenoid having 4000 turns per metre. It is found that the potential difference across the capacitor drops to 90% of its maximum value in 2.0 seconds. Estimate the average magnetic field produced at the centre of the solenoid during this period. 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×