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Angle sum Property of Quadrilateral

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Topics

Estimated time: 17 minutes
  • Introduction
  • Interior and Exterior of a Quadrilateral
  • Explanation: Sum of the Interior Angles of a Quadrilateral
  • Example 1
  • Example 2
  • Key Points Summary
CISCE: Class 6

Introduction

Have you ever noticed how many things around you have four sides? Your phone screen, a book, a football field, or the face of a brick! All these shapes are called quadrilaterals.

Understanding the properties of these shapes is crucial in fields like architecture, engineering, and even computer graphics. The most important rule about any closed, four-sided shape is what all its interior angles add up to. This is called the Angle Sum Property of a Quadrilateral.

CISCE: Class 6

Interior and Exterior of a Quadrilateral

  • The interior of a quadrilateral is the region enclosed by its sides.

  • The exterior of a quadrilateral is the space outside the figure.

  • The shaded portion of the figure is called interior of the quadrilateral ABCD. 
  • the part of the plane which is outside the quadrilateral ABCD is called exterior of quadrilateral ABCD. 
CISCE: Class 6

Explanation: Sum of the Interior Angles of a Quadrilateral

Step 1: Draw a Quadrilateral

  • It has four sides and four angles: ∠A, ∠B, ∠C, and ∠D.

Step 2: Diagonal Divides the Quadrilateral  

  • The diagonal BD divides the quadrilateral into two triangles:
    △ABD and △BDC

Step 3:  Angles in Each Triangle

  • We know that the sum of the angles of a triangle is always 180°.
  • In △ABD → ∠DAB + ABD + ADB = 180°
    In △BDC → DBC + BCD + BDC = 180°

Step 4: Combine the Angles  

  • DAB + ABC + BCD + CDA = 360°

Step 5: Conclusion

  • Therefore, the sum of the measures of the four interior angles of any quadrilateral is 360°.
CISCE: Class 6

Example 1

Angles of a quadrilateral are 85°, 95°, x° and (x + 10)°. Find the value of x.

Solution:

Sum of the angles of the quadrilateral = 360°

⇒ 85° + 95° + x° + (x + 10)° = 360°

⇒ 180° + x° + x° + 10° = 360°

⇒ 2x° + 190° = 360°

i.e., 2x° = 360° − 190° = 170°

∴ x° = `"170°"/"2"`

∴ x = 85

CISCE: Class 6

Example 2

Three angles of a quadrilateral are in the ratio 4 : 6 : 3. If the fourth angle is 100°, find the other three angles of the quadrilateral.

Solution:

Let the three angles be 4x, 6x and 3x

∴ 4x + 6x + 3x + 100° = 360°

⇒ 13x = 360° − 100° = 260° and

x = `"260°"/"13"` = 20°

∴ The other three angles are 4x, 6x and 3x

= 4 × 20°, 6 × 20° and 3 × 20°

= 80°, 120° and 60°

CISCE: Class 6

Key Points Summary

  • The sum of its interior angles is always 360°.

  • Drawing a diagonal divides it into two triangles.

  • Each triangle has a sum of angles = 180° → Total = 360°.

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