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Sum of Exterior Angles of a Polygon

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Estimated time: 19 minutes
  • Introduction
  • Properties
  • Example 1
  • Example 2
  • Key Points Summary
CISCE: Class 6

Introduction

Polygons have two types of angles we focus on: Interior (inside the shape) and Exterior (outside the shape).

The exterior angle of a polygon is the angle formed when one of its sides is extended.

CISCE: Class 6

Properties

  1. . In each case, ∠a + ∠b + ∠c = 360°.
  2. In each case: ∠a + ∠b + ∠c + ∠d = 360°
  3. In each case, ∠a + ∠b + ∠e + ∠d + ∠e = 360° and so on. 
  • The sum of all exterior angles of any polygon is always 360°, no matter how many sides it has.

  • A polygon must have at least 3 sides (triangle being the smallest polygon).

CISCE: Class 6

Example 1

If the exterior angles of a triangle are 3x°, 5x°, and 4x°, find the value of x.

Solution:

Sum of exterior angles of each polygon = 360° 

3x + 5x + 4x = 360°

12x = 360°

x = 30°

CISCE: Class 6

Example 2

Two angles of a hexagon are 100° and 120°. If the remaining four angles are equal, find each equal angle. 

Solution:

Let each equal angle be x°

Since a hexagon has six angles, the sum of all its six interior angles

                                            = 100° + 120° + x° + x° + x° + x°

                                            = 220° + 4x°

Also, the sum of the interior angles of the hexagon

                                           = (n − 2) × 180° [where n = 6]

                                           = (6 − 2) × 180°

                                           = 4 × 180° = 720°

Given:              220° + 4x° = 720°

                                    4x°  = 720° − 220° = 500°

                                      x° = `" 500°"/ "4"` = 125°

∴ Each equal angle = 125° 

CISCE: Class 6

Key Points Summary

  • The sum of all exterior angles of a polygon is always 360°.
  • Interior angle + Exterior angle = 180°

  • No polygon can have a fractional number of sides.

Example Question 1

Find measure x in the following Fig.
x + 90° + 50° + 110° = 360° .....(The sum of the measures of the external angles of any polygon is 360°.)
x + 250° = 360°
x = 110°.

Example Question 2

Find the number of sides of a regular polygon whose each exterior angle has a measure of 45°.
Total measure of all exterior angles = 360°
Measure of each exterior angle = 45°
Therefore, the number of exterior angles = `360/45` = 8
The polygon has 8 sides.

Test Yourself

Shaalaa.com | Sum of Measures of External Angles of Triangle

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