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Perimeter of a Rectangle

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Estimated time: 22 minutes
  • Introduction
  • Formula : Perimeter of a Rectangle
  • Example 1
  • Example 2
  • Example 3
  • Key Points Summary
CISCE: Class 6

Introduction

Perimeter is the distance you travel when you walk around the outside of a shape. Think of it as the length of a fence that surrounds your garden or the border around a picture frame.

For a rectangle, the perimeter is the total distance around all four sides.

CISCE: Class 6

Formula : Perimeter of a Rectangle

Perimeter of a rectangle = 2 × length + 2 × breadth

P = 2(1 + b) ⇒ (i) l = `P/2` − b, i.e., length = `"Perimeter"/2` − breadth

                         (ii) l = `P/2` − l, i.e., breadth = `"Perimeter"/2` − length

CISCE: Class 6

Example 1

The length of the rectangle below is 7 cm, and its breadth is 3 cm. Let us find its perimeter.

Solution:

Perimeter of rectangle PQRS = 2 × length + 2 × breadth

                                                = 2 × 7 + 2 × 3

                                                = 14 + 6

                                                = 20

Therefore, the perimeter of the rectangle is 20 cm.

CISCE: Class 6

Example 2

Find Perimeter:

 

Solution: ⁣

Opposite sides of a rectangle are always equal. So, AB = CD and AD = BC

                                          = AB + BC + AB + BC

                                          = 2 × AB + 2 × BC

                                          = 2 × (AB + BC)

                                          = 2 × (12 cm + 8 cm)

                                          = 2 × (20 cm)

                                          = 40 cm.

CISCE: Class 6

Example 3

Find Perimeter

Solution:

The perimeter of the rectangle = Sum of the lengths of its four sides.

= AB + BC + CD + DA

= AB + BC + AB + BC...... (Opposite sides of a rectangle are equal)

= 2 × AB + 2 × BC

= 2 × (AB + BC)

= 2 × (15 cm + 9 cm)

= 2 × (24 cm)

= 48 cm

CISCE: Class 6

Key Points Summary

  • Perimeter = distance around a shape

  • A rectangle has 4 sides (opposite sides are equal)

  • Formula: P = 2 × (l + b)

  • Always use the same units for length and width

  • Answer must include units (cm, m, etc.)

Example Question 1

An athlete takes 10 rounds of a rectangular park, 50 m long and 25 m wide. Find the total distance covered by him.

Length of the rectangular park = 50 m
Breadth of the rectangular park = 25 m
Total distance covered by the athlete in one round will be the perimeter of the park.
Now, perimeter of the rectangular park = 2 × (length + breadth)

= 2 × (50 m + 25 m)

= 2 × 75 m

= 150 m

So, the distance covered by the athlete in one round is 150 m.

Therefore, distance covered in 10 rounds = 10 × 150 m = 1500m

The total distance covered by the athlete is 1500 m.

Example Question 2

A farmer has a rectangular field of length and breadth 240 m and 180 m respectively. He wants to fence it with 3 rounds of rope as shown in the figure. What is the total length of rope he must use?

The farmer has to cover three times the perimeter of that field.

Therefore, the total length of rope required is thrice its perimeter.

Perimeter of the field = 2 × (length + breadth)

= 2 × ( 240 m + 180 m)

= 2 × 420 m

= 840 m

Total length of rope required = 3 × 840 m = 2520 m.

Example Question 3

Find the cost of fencing a rectangular park of length 250 m and breadth 175 m at the rate of Rs. 12 per metre.

Length of the rectangular park = 250 m

Breadth of the rectangular park = 175 m

Perimeter of the rectangle = 2 × (length + breadth)

= 2 × (250 m + 175 m)

= 2 × (425 m)

= 850 m

Cost of fencing 1m of park = Rs. 12

Therefore, the total cost of fencing the park = Rs. 12 × 850 = Rs. 10200

Test Yourself

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