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NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 chapter 5 - Continuity and Differentiability [Latest edition]

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Solutions for Chapter 5: Continuity and Differentiability

Below listed, you can find solutions for Chapter 5 of CBSE, Karnataka Board PUC NCERT for Mathematics Part 1 and 2 [English] Class 12.


Exercise 5.1Exercise 5.2Exercise 5.3Exercise 5.4Exercise 5.5Exercise 5.6Exercise 5.7Exercise 5.8Exercise 5.9
Exercise 5.1 [Pages 159 - 161]

NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 5 Continuity and Differentiability Exercise 5.1 [Pages 159 - 161]

1Page 159

Prove that the function f(x) = 5x – 3 is continuous at x = 0, at x = –3 and at x = 5.

1.3Page 159

Examine the following function for continuity:

f(x) = `(x^2 - 25)/(x + 5)`, x ≠ −5

2Page 159

Examine the continuity of the function f(x) = 2x2 – 1 at x = 3.

3.1Page 159

Examine the following function for continuity:

f(x) = x – 5

3.2Page 159

Examine the following function for continuity:

f(x) = `1/(x - 5)`, x ≠ 5

3.4Page 159

Examine the following function for continuity:

f(x) = |x – 5|

4Page 159

Prove that the function f(x) = xn is continuous at x = n, where n is a positive integer.

5Page 159

Is the function f defined by f(x) = `{(x", if"  x<=1),(5", if"  x > 1):}`  continuous at x = 0? At x = 1? At x = 2?

6Page 159

Find all points of discontinuity of f, where f is defined by:

f(x) = `{(2x + 3", if"  x<=2),(2x - 3", if"  x > 2):}`

7Page 159

Find all points of discontinuity of f, where f is defined by:

f(x) = `{(|x|+3", if"  x<= -3),(-2x", if" -3 < x < 3),(6x + 2", if"  x >= 3):}`

8Page 159

Find all points of discontinuity of f, where f is defined by:

f(x) = `{(|x|/x", if"  x != 0),(0", if"  x = 0):}`

9Page 159

Find all points of discontinuity of f, where f is defined by:

f(x) = `{(x/|x|", if"  x<0),(-1", if"  x >= 0):}`

10Page 159

Find all points of discontinuity of f, where f is defined by:

f(x) = `{(x+1", if"  x>=1),(x^2+1", if"  x < 1):}`

11Page 159

Find all points of discontinuity of f, where f is defined by:

f(x) = `{(x^3 - 3", if"  x <= 2),(x^2 + 1", if"  x > 2):}`

12Page 159

Find all points of discontinuity of f, where f is defined by:

f(x) = `{(x^10 - 1", if"  x<=1),(x^2", if"  x > 1):}`

13Page 159

Is the function defined by f(x) = `{(x+5", if"  x <= 1),(x -5", if"  x > 1):}` a continuous function?

14Page 160

Discuss the continuity of the function f, where f is defined by:

f(x) = `{(3", if"  0 <= x <= 1),(4", if"  1 < x < 3),(5", if"  3 <= x <= 10):}`

15Page 160

Discuss the continuity of the function f, where f is defined by:

f(x) = `{(2x", if"  x < 0),(0", if"  0 <= x <= 1),(4x", if"  x > 1):}`

16Page 160

Discuss the continuity of the function f, where f is defined by:

f(x) = `{(-2", if"  x <= -1),(2x", if" -1 < x <= 1),(2", if"  x > 1):}`

17Page 160

Find the relationship between a and b so that the function f defined by f(x) = `{(ax + 1", if"  x<= 3),(bx + 3", if"  x > 3):}` is continuous at x = 3.

18Page 160

For what value of λ is the function defined by f(x) = `{(λ(x^2 - 2x)", if"  x <= 0),(4x+ 1", if"  x > 0):}` continuous at x = 0? What about continuity at x = 1?

19Page 160

Show that the function defined by g(x) = x − [x] is discontinuous at all integral points. Here [x] denotes the greatest integer less than or equal to x.

20Page 160

Is the function defined by f(x) = x2 − sin x + 5 continuous at x = π?

21Page 160

Discuss the continuity of the following function:

f(x) = sin x × cos x

22Page 160

Discuss the continuity of the cosine, cosecant, secant and cotangent functions.

23Page 160

Find the points of discontinuity of f, where f(x) = `{(sinx/x", if"  x<0),(x + 1", if"  x >= 0):}`.

24Page 160

Determine if f defined by f(x) = `{(x^2 sin  1/x", if"  x != 0),(0", if"  x = 0):}` is a continuous function?

25Page 161

Examine the continuity of f, where f is defined by:

f(x) = `{(sin x - cos x", if"  x != 0),(-1", if"  x = 0):}`

26Page 161

Find the value of k so that the function f is continuous at the indicated point.

f(x) = `{((kcosx)/(pi-2x)", if"  x != pi/2),(3", if"  x = pi/2):}` at x = `"pi/2`

27Page 161

Find the value of k so that the function f is continuous at the indicated point.

f(x) = `{(kx^2", if"  x<= 2),(3", if"  x > 2):}` at x = 2

28Page 161

Find the value of k so that the function f is continuous at the indicated point.

f(x) = `{(kx +1", if"  x<= pi),(cos x", if"  x > pi):}` at x = π

29Page 161

Find the value of k so that the function f is continuous at the indicated point.

f(x) = `{(kx + 1", if"  x <= 5),(3x - 5", if"  x > 5):}` at x = 5

30Page 161

Find the values of a and b such that the function defined by f(x) = `{(5", if"  x <= 2),(ax +b", if"  2 < x < 10),(21", if"  x >= 10):}` is a continuous function.

31Page 161

Show that the function defined by f(x) = cos (x2) is a continuous function.

32Page 161

Show that the function defined by f(x) = |cos x| is a continuous function.

33Page 161

Examine that sin |x| is a continuous function.

34Page 161

Find all the points of discontinuity of f defined by f(x) = |x| − |x + 1|.

Exercise 5.2 [Page 166]

NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 5 Continuity and Differentiability Exercise 5.2 [Page 166]

1Page 166

Differentiate the function with respect to x.

sin (x2 + 5)

2Page 166

Differentiate the function with respect to x.

cos (sin x)

3Page 166

Differentiate the function with respect to x.

sin (ax + b)

4Page 166

Differentiate the function with respect to x.

`sec(tan (sqrtx))`

5Page 166

Differentiate the function with respect to x.

`(sin (ax + b))/cos (cx + d)`

6Page 166

Differentiate the function with respect to x. 

cos x3 . sin2 (x5)

7Page 166

Differentiate the function with respect to x. 

`2sqrt(cot(x^2))`

8Page 166

Differentiate the function with respect to x.

`cos (sqrtx)`

10Page 166

Prove that the function f given by f(x) = |x − 1|, x ∈ R is not differentiable at x = 1.

Exercise 5.3 [Page 169]

NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 5 Continuity and Differentiability Exercise 5.3 [Page 169]

1Page 169

Find `bb(dy/dx)` in the following:

2x + 3y = sin x

2Page 169

Find `bb(dy/dx)` in the following:

2x + 3y = sin y

3Page 169

Find `bb(dy/dx)` in the following:

ax + by2 = cos y

4Page 169

Find `bb(dy/dx)` in the following:

xy + y2 = tan x + y

5Page 169

Find `bb(dy/dx)` in the following:

x2 + xy + y2 = 100

6Page 169

Find `bb(dy/dx)` in the following:

x3 + x2y + xy2 + y3 = 81

7Page 169

Find `bb(dy/dx)` in the following:

sin2 y + cos xy = k

8Page 169

Find `bb(dy/dx)` in the following:

sin2 x + cos2 y = 1

9Page 169

Find `bb(dy/dx)` in the following:

`y = sin^(-1)((2x)/(1+x^2))`

10Page 169

Find `bb(dy/dx)` in the following:

`y = tan^(-1) ((3x -x^3)/(1 - 3x^2)), - 1/sqrt3 < x < 1/sqrt3`

11Page 169

Find `bb(dy/dx)` in the following:

y = `cos^(-1) ((1-x^2)/(1+x^2))`, 0 < x < 1

12Page 169

Find `bb(dy/dx)` in the following:

y = `sin^(-1) ((1-x^2)/(1+x^2))`, 0 < x < 1

13Page 169

Find `bb(dy/dx)` in the following:

y = `cos^(-1) ((2x)/(1+x^2))`, −1 < x < 1

14Page 169

Find `bb(dy/dx)` in the following:

y = `sin^(-1)(2xsqrt(1-x^2)), -1/sqrt2 < x < 1/sqrt2`

15Page 169

Find `bb(dy/dx)` in the following:

y = `sec^(-1) (1/(2x^2 - 1)), 0 < x < 1/sqrt2`

Exercise 5.4 [Page 174]

NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 5 Continuity and Differentiability Exercise 5.4 [Page 174]

1Page 174

Differentiate the following w.r.t. x:

`e^x/sinx`

2Page 147

Differentiate the following w.r.t. x: 

`e^(sin^(-1) x)`

3Page 174

Differentiate the following w.r.t. x:

`e^(x^3)`

4Page 174

Differentiate the following w.r.t. x: 

sin (tan–1 e–x)

5Page 174

Differentiate the following w.r.t. x:

log (cos ex)

6Page 174

Differentiate the following w.r.t. x:

`e^x + e^(x^2) + "..." + e^(x^5)`

7Page 174

Differentiate the following w.r.t. x:

`sqrt(e^(sqrtx))`, x > 0

8Page 174

Differentiate the following w.r.t. x:

log (log x), x > 1

9Page 174

Differentiate the following w.r.t. x: 

`cos x/log x`, x > 0

10Page 174

Differentiate the following w.r.t. x:

cos (log x + ex), x > 0

Exercise 5.5 [Pages 178 - 179]

NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 5 Continuity and Differentiability Exercise 5.5 [Pages 178 - 179]

1Page 178

Differentiate the function with respect to x. 

cos x . cos 2x . cos 3x

2Page 178

Differentiate the function with respect to x.

`sqrt(((x-1)(x-2))/((x-3)(x-4)(x-5)))`

3Page 178

Differentiate the function with respect to x.

(log x)cos x

4Page 178

Differentiate the function with respect to x.

xx − 2sin x

5Page 178

Differentiate the function with respect to x.

(x + 3)2 . (x + 4)3 . (x + 5)4

6Page 178

Differentiate the function with respect to x.

`(x + 1/x)^x + x^((1+1/x))`

7Page 178

Differentiate the function with respect to x.

(log x)x + xlog x

8Page 178

Differentiate the function with respect to x.

`(sin x)^x + sin^(-1) sqrtx`

9Page 178

Differentiate the function with respect to x.

xsin x + (sin x)cos x

10Page 178

Differentiate the function with respect to x.

`x^(xcosx) + (x^2 + 1)/(x^2 -1)`

11Page 178

Differentiate the function with respect to x.

`(x cos x)^x + (x sin x)^(1/x)`

12Page 178

Find `bb(dy/dx)` for the given function:

xy + yx = 1

13Page 178

Find `bb(dy/dx)` for the given function:

yx = xy

14Page 178

Find `bb(dy/dx)` for the given function:

(cos x)y = (cos y)x

15Page 178

Find `bb(dy/dx)` for the given function:

xy = `e^((x - y))`

16Page 178

Find the derivative of the function given by f(x) = (1 + x) (1 + x2) (1 + x4) (1 + x8) and hence find f′(1).

17Page 178

Differentiate (x2 – 5x + 8) (x3 + 7x + 9) in three ways mentioned below:

  1. By using the product rule.
  2. By expanding the product to obtain a single polynomial.
  3. By logarithmic differentiation.

Do they all give the same answer?

18Page 179

If u, v and w are functions of x, then show that `d/dx(u.v.w) = (du)/dx v.w + u. (dv)/dx.w + u.v. (dw)/dx` in two ways-first by repeated application of product rule, second by logarithmic differentiation.

Exercise 5.6 [Page 181]

NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 5 Continuity and Differentiability Exercise 5.6 [Page 181]

1Page 181

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = 2at2, y = at4

3Page 181

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = sin t, y = cos 2t

4Page 181

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = 4t, y = `4/y`

5Page 181

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = cos θ – cos 2θ, y = sin θ – sin 2θ

5.6Page 181

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = a cos θ, y = b cos θ

6Page 181

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = a (θ – sin θ), y = a (1 + cos θ)

7Page 181

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

`x = (sin^3t)/sqrt(cos 2t), y = (cos^3t)/sqrt(cos 2t)`

8Page 181

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = `a(cos t + log tan  t/2)`, y = a sin t

9Page 181

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = a sec θ, y = b tan θ

10Page 181

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = a (cos θ + θ sin θ), y = a (sin θ – θ cos θ)

11Page 181

If x = `sqrt(a^(sin^(-1)t))`, y = `sqrt(a^(cos^(-1)t))` show that `dy/dx = - y/x`.

Exercise 5.7 [Page 183]

NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 5 Continuity and Differentiability Exercise 5.7 [Page 183]

1Page 183

Find the second order derivative of the function.

x2 + 3x + 2

3Page 183

Find the second order derivative of the function.

x . cos x

4Page 183

Find the second order derivative of the function.

log x

5Page 183

Find the second order derivative of the function.

x3 log x

6Page 183

Find the second order derivative of the function.

ex sin 5x

7Page 183

Find the second order derivative of the function.

e6x cos 3x

8Page 183

Find the second order derivative of the function.

tan–1 x

9Page 183

Find the second order derivative of the function.

log (log x)

10Page 183

Find the second order derivative of the function.

sin (log x)

11Page 183

If y = 5 cos x – 3 sin x, prove that `(d^2y)/(dx^2) + y = 0`.

12Page 184

If y = cos–1 x, find `(d^2y)/dx^2` in terms of y alone.

13Page 184

If y = 3 cos (log x) + 4 sin (log x), show that x2y2 + xy1 + y = 0.

14Page 184

If y = Aemx + Benx, show that `(d^2y)/dx^2 - (m+ n) (dy)/dx + mny = 0`.

15Page 184

If y = 500e7x + 600e–7x, show that `(d^2y)/(dx^2)` = 49y.

16Page 184

If ey (x + 1) = 1, show that `(d^2y)/(dx^2) = (dy/dx)^2`.

17Page 184

If y = (tan–1 x)2, show that (x2 + 1)2 y2 + 2x (x2 + 1) y1 = 2

183Page 183

Find the second order derivative of the function.

x20

Exercise 5.8 [Page 186]

NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 5 Continuity and Differentiability Exercise 5.8 [Page 186]

1Page 186

Verify Rolle’s theorem for the function f (x) = x2 + 2x – 8, x ∈ [– 4, 2].

2.1Page 186

Examine if Rolle’s Theorem is applicable to any of the following functions. Can you say some thing about the converse of Rolle’s Theorem from these examples?

f (x) = [x] for x ∈ [5, 9]

2.2Page 186

Examine if Rolle’s Theorem is applicable to any of the following functions. Can you say some thing about the converse of Rolle’s Theorem from these examples?

f (x) = [x] for x ∈ [– 2, 2]

2.3Page 186

Examine if Rolle’s Theorem is applicable to any of the following functions. Can you say some thing about the converse of Rolle’s Theorem from these examples?

f (x) = x2 – 1 for x ∈ [1, 2]

3Page 186

If f : [– 5, 5] → R is a differentiable function and if f ′(x) does not vanish anywhere, then prove that f (– 5) ≠ f (5).

4Page 186

Verify Mean Value Theorem, if f (x) = x2 – 4x – 3 in the interval [a, b], where a = 1 and b = 4.

5Page 186

Verify Mean Value Theorem, if f (x) = x3 – 5x2 – 3x in the interval [a, b], where a = 1 and b = 3. Find all c ∈ (1, 3) for which f ′(c) = 0.

6Page 186

Examine the applicability of Mean Value Theorem for all three functions given in the above exercise 2. 

Exercise 5.9 [Pages 191 - 192]

NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 5 Continuity and Differentiability Exercise 5.9 [Pages 191 - 192]

1Page 191

Differentiate the function with respect to x:

(3x2 – 9x + 5)9

2Page 191

Differentiate the function with respect to x:

sin3 x + cos6 x

3Page 191

Differentiate the function with respect to x:

`(5x)^(3cos 2x)`

4Page 191

Differentiate the function with respect to x:

`sin^(–1)(xsqrtx), 0 ≤ x ≤ 1`

5Page 191

Differentiate the function with respect to x:

`(cos^(-1)  x/2)/sqrt(2x+7)`, −2 < x < 2

6Page 191

Differentiate the function with respect to x:

`cot^(-1) [(sqrt(1+sinx) + sqrt(1-sinx))/(sqrt(1+sinx) - sqrt(1-sinx))], 0 < x < pi/2`

7Page 191

Differentiate the function with respect to x:

(log x)log x, x > 1

8Page 191

Differentiate the function with respect to x:

cos (a cos x + b sin x), for some constant a and b.

9Page 191

Differentiate the function with respect to x:

`(sin x - cos x)^((sin x - cos x)), pi/4 < x < (3pi)/4`

10Page 191

Differentiate the function with respect to x:

xx + xa + ax + aa, for some fixed a > 0 and x > 0

11Page 191

Differentiate the function with respect to x:

`x^(x^2 -3) + (x -3)^(x^2)`, for x > 3

12Page 191

Find `dy/dx`, if y = 12 (1 – cos t), x = 10 (t – sin t), `-pi/2 < t < pi/2`.

13Page 191

Find `dy/dx`, if y = `sin^-1 x + sin^-1 sqrt (1 - x^2)`, 0 < x < 1.

14Page 191

If `xsqrt(1+y) + y  sqrt(1+x) = 0`, for, −1 < x < 1, prove that `dy/dx = -1/(1+ x)^2`.

15Page 191

If (x – a)2 + (y – b)2 = c2, for some c > 0, prove that `[1+ (dy/dx)^2]^(3/2)/((d^2y)/dx^2)` is a constant independent of a and b.

16Page 192

If cos y = x cos (a + y), with cos a ≠ ± 1, prove that `dy/dx = cos^2(a+y)/(sin a)`.

17Page 192

If x = a (cos t + t sin t) and y = a (sin t – t cos t), find `(d^2y)/dx^2`.

18Page 192

If f(x) = |x|3, show that f"(x) exists for all real x and find it.

19Page 192

Using mathematical induction prove that  `d/(dx) (x^n) = nx^(n -1)` for all positive integers n.

20Page 192

Using the fact that sin (A + B) = sin A cos B + cos A sin B and the differentiation, obtain the sum formula for cosines.

21Page 192

Does there exist a function which is continuos everywhere but not differentiable at exactly two points? Justify your answer?

22Page 192

If y = `[(f(x), g(x), h(x)),(l, m,n),(a,b,c)]`, prove that `dy/dx = |(f'(x), g'(x), h'(x)),(l,m, n),(a,b,c)|`.

23Page 192

If y = `e^(acos^(-1)x)`, −1 ≤ x ≤ 1, show that `(1- x^2) (d^2y)/(dx^2) -x dy/dx - a^2y = 0`.

Solutions for 5: Continuity and Differentiability

Exercise 5.1Exercise 5.2Exercise 5.3Exercise 5.4Exercise 5.5Exercise 5.6Exercise 5.7Exercise 5.8Exercise 5.9

NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 chapter 5 - Continuity and Differentiability

Shaalaa.com has the CBSE, Karnataka Board PUC Mathematics Mathematics Part 1 and 2 [English] Class 12 CBSE, Karnataka Board PUC solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. NCERT solutions for Mathematics Mathematics Part 1 and 2 [English] Class 12 CBSE, Karnataka Board PUC 5 (Continuity and Differentiability) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. NCERT textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Mathematics Part 1 and 2 [English] Class 12 chapter 5 Continuity and Differentiability are Algebra of Continuous Functions, Concept of Differentiability, Continuous and Discontinuous Functions, Derivative of Composite Functions, Exponential and Logarithmic Functions, Logarithmic Differentiation, Derivatives of Functions in Parametric Forms, Second Order Derivative, Derivative of Implicit Functions, Derivative of Inverse Function, Overview of Continuity and Differentiability, Algebra of Continuous Functions, Concept of Differentiability, Continuous and Discontinuous Functions, Derivative of Composite Functions, Exponential and Logarithmic Functions, Logarithmic Differentiation, Derivatives of Functions in Parametric Forms, Second Order Derivative, Derivative of Implicit Functions, Derivative of Inverse Function, Overview of Continuity and Differentiability.

Using NCERT Mathematics Part 1 and 2 [English] Class 12 solutions Continuity and Differentiability exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in NCERT Solutions are essential questions that can be asked in the final exam. Maximum CBSE, Karnataka Board PUC Mathematics Part 1 and 2 [English] Class 12 students prefer NCERT Textbook Solutions to score more in exams.

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