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Question
Find the second order derivative of the function.
log x
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Solution
Let, y = log x
Differentiating both sides with respect to x,
`dy/dx = d/dx log x`
`dy/dx = 1/x`
Differentiating both sides again with respect to x,
`(d^2y)/(dx^2 ) = d/dx [1/x]`
= `d/dx [x^-1]`
= `-1 x^(-1-1)`
= −1 x−2
= `-1/x^2`
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