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Question
Find `("d"^2"y")/"dx"^2`, if y = `"x"^-7`
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Solution
y = `"x"^-7`
Differentiating both sides w.r.t.x, we get
`"dy"/"dx" = -7"x"^-8`
Again, differentiating both sides w.r.t. x , we get
`("d"^2"y")/"dx"^2 = -7 * "d"/"dx" ("x"^-8)`
`= - 7(-8)"x"^-9`
∴ `("d"^2"y")/"dx"^2 = 56"x"^-9`
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