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Question
Find `("d"^2"y")/"dx"^2`, if y = `"x"^5`
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Solution
y = `"x"^5`
Differentiating both sides w.r.t.x, we get
`"dy"/"dx" = 5"x"^4`
Again, differentiating both sides w.r.t. x , we get
`("d"^2"y")/"dx"^2 = 5 * "d"/"dx" ("x"^4)`
`= 5(4"x"^3)`
∴ `("d"^2"y")/"dx"^2 = 20"x"^3`
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