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Question
Find `("d"^2"y")/"dx"^2`, if y = `"e"^"log x"`
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Solution
y = `"e"^"log x"`
y = x
Differentiating both sides w.r.t.x, we get
`d/dx` (y) = `d/dx` (x)
`"dy"/"dx" = 1`
Again, by differentiating both sides w.r.t.x, we get
`d/dx (dy/dx)` = `d/dx(1)`
`("d"^2"y")/"dx"^2 = 0`
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