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If y = 5 cos x – 3 sin x, prove that (d^2y)/(dx^2) + y = 0.

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Question

If y = 5 cos x – 3 sin x, prove that `(d^2y)/(dx^2) + y = 0`.

Theorem
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Solution

Given, y = 5 cos x – 3 sin x

Differentiating both sides with respect to x,

`dy/dx = 5 d/dx cos x - 3 d/dx sin x`

= 5 (−sin x) − 3 cos x

= −5 sin x − 3 cos x

Differentiating both sides again with respect to x,

`(d^2 y)/dx = - 5 d/dx sin x - 3 d/dx cos x`

= −5 cos x − 3 (−sin x)

= 3 sin x − 5 cos x

Hence, `(d^2 y)/dx^2 + y` = 0

(3 sin x − 5 cos x) + (5 cos x − 3 sin x) = 0 ...(On substituting the value of y)

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Chapter 5: Continuity and Differentiability - Exercise 5.7 [Page 183]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 5 Continuity and Differentiability
Exercise 5.7 | Q 11 | Page 183

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