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Question
Find `("d"^2"y")/"dx"^2`, if y = log (x).
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Solution
y = log x
Differentiating both sides w.r.t.x, we get
`"dy"/"dx" = 1/"x"`
Again, differentiating both sides w.r.t. x , we get
`("d"^2"y")/"dx"^2 = (- 1)/"x"^2`
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