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Find all points of discontinuity of f, where f is defined by f(x) = {x10 - 1, if x ≤ 1, x2 if x > 1 - Mathematics

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Question

Find all points of discontinuity of f, where f is defined by:

f(x) = `{(x^10 - 1", if"  x<=1),(x^2", if"  x > 1):}`

Sum
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Solution

f(x) = `{(x^10 - 1", if"  x<=1),(x^2", if"  x > 1):}`

For x < 1, f(x) = x10 − 1 and

x > 1, f(x) = x2 is a polynomial function.

So this is a function.

At x = 1,

`lim_(x -> 1^-)` f(x) = `lim_(x -> 1^-)` (x10 − 1)

= `lim_(h -> 0)` [(1 − h)10 − 1]

= (1 − 0)10 − 1

= 1 − 1

= 0

`lim_(x -> 1^+)` f(x) = `lim_(x -> 1^+)` (x2)

= `lim_(h -> 0)` (1 + h)2

= `lim_(h -> 0)` (1 + h2 + 2h)

= 1

Hence, f is not continuous at x = 1.

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Chapter 5: Continuity and Differentiability - Exercise 5.1 [Page 159]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 5 Continuity and Differentiability
Exercise 5.1 | Q 12 | Page 159
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