English

If x = sqrt(a^(sin^(-1)t)), y = sqrt(a^(cos^(-1)t)) show that dy/dx = - y/x. - Mathematics

Advertisements
Advertisements

Question

If x = `sqrt(a^(sin^(-1)t))`, y = `sqrt(a^(cos^(-1)t))` show that `dy/dx = - y/x`.

Sum
Advertisements

Solution

Given, x = `sqrt(a^(sin^(-1)t))` and y = `sqrt(a^(cos^(-1)t))`

`dx/dt = 1/2 . 1/(sqrt(a^(sin^(-1)t))). d/dt a ^(sin^(-1)t)`

= `1/2 . 1/ sqrt (a^(sin^(-1)t)). a^(sin^(-1)t) . log a d/dt sin^-1 t`

= `sqrt(a^(sin^(-1)t))/2. log a . 1/ (sqrt(1-t^2)`

`dy/dt = 1/2. 1/ sqrt (a^(cos^(-1)t)). d/dt a^(cos^(-1)t)`

= `1/2 . 1/sqrt (a^(cos^(-1)t)). a^( cos^(-1)t) . log a. (-1)/(sqrt (1 - t^2))`

= `sqrt (a^(cos^(-1)t))/2 .log a (-1)/sqrt(1 - t^2)`

`∴ dy/dx = (dy/dt)/(dx/dt)`

= `(sqrt (a^(cos^(-1)t))/2. log a. (-1)/ sqrt(1 - t^2))/( sqrt (a^(sin^(-1)t))/2 . log a . 1/ sqrt (1 - t^2))`

= `(-sqrt( a^(cos^(-1)t)))/ sqrt (a^(sin^(-1)t))`

= `(-y)/x`

shaalaa.com
  Is there an error in this question or solution?
Chapter 5: Continuity and Differentiability - Exercise 5.6 [Page 181]

APPEARS IN

NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 5 Continuity and Differentiability
Exercise 5.6 | Q 11 | Page 181

RELATED QUESTIONS

If x = f(t), y = g(t) are differentiable functions of parammeter ‘ t ’ then prove that y is a differentiable function of 'x' and  hence, find dy/dx if x=a cost, y=a sint


If `x=a(t-1/t),y=a(t+1/t)`, then show that `dy/dx=x/y`


If y =1 − cos θ, x = 1 − sin θ, then `dy/dx  "at"  θ =pi/4` is ______


If x = a sin 2t (1 + cos 2t) and y = b cos 2t (1 – cos 2t) then find `dy/dx `

 


If x = cos t (3 – 2 cos2 t) and y = sin t (3 – 2 sin2 t), find the value of dx/dy at t =4/π.


Derivatives of  tan3θ with respect to sec3θ at θ=π/3 is

(A)` 3/2`

(B) `sqrt3/2`

(C) `1/2`

(D) `-sqrt3/2`


If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = a cos θ, y = b cos θ


If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = 4t, y = `4/y`


If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = `a(cos t + log tan  t/2)`, y = a sin t


If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = a sec θ, y = b tan θ


If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = a (cos θ + θ sin θ), y = a (sin θ – θ cos θ)


If `x = acos^3t`, `y = asin^3 t`,

Show that `(dy)/(dx) =- (y/x)^(1/3)`


IF `y = e^(sin-1x)   and  z =e^(-cos-1x),` prove that `dy/dz = e^x//2`


The cost C of producing x articles is given as C = x3-16x2 + 47x.  For what values of x, with the average cost is decreasing'?  


Evaluate : `int  (sec^2 x)/(tan^2 x + 4)` dx


sin x = `(2"t")/(1 + "t"^2)`, tan y = `(2"t")/(1 - "t"^2)`


If x = ecos2t and y = esin2t, prove that `"dy"/"dx" = (-y log x)/(xlogy)`


If x = asin2t (1 + cos2t) and y = b cos2t (1–cos2t), show that `("dy"/"dx")_("at  t" = pi/4) = "b"/"a"`


If x = 3sint – sin 3t, y = 3cost – cos 3t, find `"dy"/"dx"` at t = `pi/3`


Differentiate `x/sinx` w.r.t. sin x


Differentiate `tan^-1 ((sqrt(1 + x^2) - 1)/x)` w.r.t. tan–1x, when x ≠ 0


If x = sint and y = sin pt, prove that `(1 - x^2) ("d"^2"y")/("dx"^2) - x "dy"/"dx" + "p"^2y` = 0


Derivative of x2 w.r.t. x3 is ______.


If y `= "Ae"^(5"x") + "Be"^(-5"x") "x"  "then"  ("d"^2 "y")/"dx"^2` is equal to ____________.


Form the point of intersection (P) of lines given by x2 – y2 – 2x + 2y = 0, points A, B, C, Dare taken on the lines at a distance of `2sqrt(2)` units to form a quadrilateral whose area is A1 and the area of the quadrilateral formed by joining the circumcentres of ΔPAB, ΔPBC, ΔPCD, ΔPDA is A2, then `A_1/A_2` equals


If x = `a[cosθ + logtan  θ/2]`, y = asinθ then `(dy)/(dx)` = ______.


Let a function y = f(x) is defined by x = eθsinθ and y = θesinθ, where θ is a real parameter, then value of `lim_(θ→0)`f'(x) is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×