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Question
If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.
x = a cos θ, y = b cos θ
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Solution
Given, x = a cos θ and y = b cos θ
Differentiating both sides with respect to θ,
`dx/(dθ)` = −a sin θ
`dy/(dθ)` = −b sin θ
`dy/dx = (dy/(dθ))/(dx/(dθ))`
= `(-b sin θ)/(- a sin θ)`
= `b/a`
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