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Question
If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.
x = 4t, y = `4/y`
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Solution
Given, x = 4t and y = `4/t`
Differentiating both sides with respect to t,
`dx/dt` = 4 and `dy/dt = (-4)/t^2`
Hence, `dy/dx = (dy/dt)/(dx/dt)`
= `((-4)/t^2)/4`
= `(- 1)/t^2`
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