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Examine the following function for continuity: f(x) = |x – 5| - Mathematics

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Question

Examine the following function for continuity:

f(x) = |x – 5|

Sum
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Solution

Let f(x) = |x – 5|

`lim_(x->a^+)` f(x) = `lim_(h->0)` |a + h − 5|

= |a − 5|

= a − 5

`lim_(x->a^-)` f(x) = `lim_(h->0)` |a − h − 5|

= |a − 5|

= a − 5

f(a) = |a − 5| = a − 5

∴ `lim_(x->a^+)` f(x) = `lim_(x->a^-)` f(x) = f(a)

Hence, the given function f(x) = |x − 5| is continuous.

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Chapter 5: Continuity and Differentiability - Exercise 5.1 [Page 159]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 5 Continuity and Differentiability
Exercise 5.1 | Q 3.4 | Page 159

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