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NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 chapter 2 - Inverse Trigonometric Functions [Latest edition]

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Solutions for Chapter 2: Inverse Trigonometric Functions

Below listed, you can find solutions for Chapter 2 of CBSE, Karnataka Board PUC NCERT for Mathematics Part 1 and 2 [English] Class 12.


Exercise 2.1Exercise 2.2Exercise 2.3
Exercise 2.1 [Pages 41 - 42]

NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 2 Inverse Trigonometric Functions Exercise 2.1 [Pages 41 - 42]

1Page 41

Find the principal value of the following:

`sin^(-1) (-1/2)`

2Page 41

Find the principal value of the following:

`cos^(-1) (sqrt3/2)`

3Page 41

Find the principal value of the following:

cosec−1 (2)

4Page 41

Find the principal value of the following:

`tan^(-1) (-sqrt3)`

5Page 41

Find the principal value of the following:

`cos^(-1) (-1/2)`

6Page 41

Find the principal value of the following:

tan−1 (−1)

7Page 42

Find the principal value of the following:

`sec^(-1) (2/sqrt(3))`

8Page 42

Find the principal value of the following:

`cot^(-1) (sqrt3)`

9Page 42

Find the principal value of the following:

`cos^(-1) (-1/sqrt2)`

10Page 42

Find the principal value of the following:

`"cosec"^(-1)(-sqrt2)`

10Page 42

Find the value of the following:

`tan^(-1)(1) + cos^(-1) (-1/2) + sin^(-1) (-1/2)`

12Page 42

Find the value of the following:

`cos^(-1) (1/2) + 2 sin^(-1)(1/2)`

13Page 42

If sin−1 x = y, then ______.

  • 0 ≤ y ≤ π

  • `-pi/2 ≤ y ≤ pi/2`

  • 0 < y < π

  • `-pi/2 < y < pi/2`

14Page 42

`tan^(-1) sqrt3 - sec^(-1)(-2)` is equal to ______.

  • π

  • `-pi/3`

  • `pi/3`

  • `(2pi)/3`

Exercise 2.2 [Pages 47 - 48]

NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 2 Inverse Trigonometric Functions Exercise 2.2 [Pages 47 - 48]

1Page 47

Prove the following:

3 sin−1 x = sin−1 (3x − 4x3), `x ∈ [-1/2, 1/2]`

2Page 47

Prove the following: 

3cos−1x = cos−1(4x3 − 3x), `x ∈ [1/2, 1]`

3Page 47

Prove `tan^(-1)  2/11 + tan^(-1)  7/24 = tan^(-1)  1/2`

4Page 47

Prove `2 tan^(-1)  1/2 + tan^(-1)  1/7 = tan^(-1)  31/17`

5Page 47

Write the following function in the simplest form:

`tan^(-1)  (sqrt(1+x^2) -1)/x`, x ≠ 0

6Page 47

Write the function in the simplest form: `tan^(-1)  1/(sqrt(x^2 - 1)), |x| > 1`

7Page 47

Write the following function in the simplest form:

`tan^(-1) (sqrt((1-cos x)/(1 + cos x)))`, 0 < x < π

8Page 47

Write the function in the simplest form:  `tan^(-1)  ((cos x - sin x)/(cos x + sin x)) `,` 0 < x < pi`

9Page 48

Write the following function in the simplest form:

`tan^(-1)  x/(sqrt(a^2 - x^2))`, |x| < a

10Page 48

Write the following function in the simplest form:

`tan^(-1) ((3a^2 x - x^3)/(a^3 - 3ax^2)), a > 0; (-a)/sqrt3 < x < a/sqrt3`

11Page 48

Find the value of the following:

`tan^-1 [2 cos (2  sin^-1  1/2)]`

12Page 48

Find the value of `cot(tan^(-1) a + cot^(-1) a)`

13Page 48

Find the value of the following:

`tan  1/2 [sin^(-1)  (2x)/(1+ x^2) + cos^(-1)  (1-y^2)/(1+y^2)]`, |x| < 1, y > 0 and xy < 1

14Page 48

if `sin(sin^(-1)  1/5 + cos^(-1) x)  = 1` then find the value of x

15Page 48

if `tan^(-1)  (x-1)/(x - 2) + tan^(-1)  (x + 1)/(x + 2) = pi/4` then find the value of x.

16Page 48

Find the value of the given expression.

`sin^(-1) (sin  (2pi)/3)`

17Page 48

Find the value of the given expression.

`tan^(-1) (tan  (3pi)/4)`

18Page 48

Find the value of the given expression.

`tan(sin^(-1)  3/5 + cot^(-1)  3/2)`

19Page 48

`cos^(-1) (cos  (7pi)/6)` is equal to ______.

  • `(7pi)/6`

  • `(5pi)/6`

  • `pi/3`

  • `pi/6`

21Page 48

`sin[pi/3 - sin^(-1) (-1/2)]` is equal to ______.

  • `1/2`

  • `1/3`

  • `1/4`

  • 1

Exercise 2.3 [Pages 51 - 52]

NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 2 Inverse Trigonometric Functions Exercise 2.3 [Pages 51 - 52]

1Page 51

Find the value of the following:

`cos^(-1) (cos  (13pi)/6)`

2Page 51

Find the value of the following:

`tan^(-1) (tan  (7pi)/6)`

3Page 51

Show that `2sin^-1(3/5) = tan^-1(24/7)`

4Page 51

Prove that:

`sin^(-1)  8/17 + sin^(-1)  3/5 = tan^(-1)  77/36`

5Page 51

Prove that:

`cos^(-1)  4/5 + cos^(-1)  12/13 = cos^(-1)  33/65`

6Page 51

Prove that:

`cos^(-1)  12/13 + sin^(-1)  3/5 = sin^(-1)  56/65`

7Page 51

Prove that:

`tan^(-1)  63/16 = sin^(-1)  5/13 + cos^(-1)  3/5`

8Page 51

Prove `tan^(-1)   1/5 + tan^(-1)  (1/7) + tan^(-1)  1/3 + tan^(-1)  1/8 = pi/4`

9Page 52

Prove that:

`tan^(-1) sqrtx = 1/2 cos^(-1)  (1-x)/(1+x)`, x ∈ [0, 1]

10Page 52

Prove that:

`cot^(-1)  ((sqrt(1+sin x) + sqrt(1-sinx))/(sqrt(1+sin x) - sqrt(1- sinx))) = x/2, x in (0, pi/4)`

11Page 52

Prove that:

`tan^-1 ((sqrt(1 + x) - sqrt(1 - x))/(sqrt(1 + x) + sqrt(1 - x))) = pi/4 - 1/2 cos^-1 x`, for `- 1/sqrt2 ≤ x ≤ 1`

[Hint: Put x =  cos 2θ]

12Page 52

Prove `(9pi)/8 - 9/4  sin^(-1)  1/3 = 9/4 sin^(-1)  (2sqrt2)/3`

13Page 52

Solve the following equation:

2 tan−1 (cos x) = tan−1 (2 cosec x)

14Page 52

Solve the following equation for x:

`tan^-1((1-x)/(1+x))-1/2 tan^-1x` = 0, where x > 0

15Page 52

sin (tan–1 x), |x| < 1 is equal to ______.

  • `x/(sqrt(1-x^2))`

  • `1/sqrt(1-x^2)`

  • `1/sqrt(1+x^2)`

  • `x/(sqrt(1+ x^2))`

16Page 52

sin–1 (1 – x) – 2 sin–1 x = `pi/2`, then x is equal to ______.

  • `0, 1/2`

  • `1, 1/2`

  • 0

  • `1/2`

17Page 52

Solve  `tan^(-1) -  tan^(-1)  (x - y)/(x+y)` is equal to

(A) `pi/2`

(B). `pi/3` 

(C) `pi/4` 

(D) `(-3pi)/4`

Solutions for 2: Inverse Trigonometric Functions

Exercise 2.1Exercise 2.2Exercise 2.3

NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 chapter 2 - Inverse Trigonometric Functions

Shaalaa.com has the CBSE, Karnataka Board PUC Mathematics Mathematics Part 1 and 2 [English] Class 12 CBSE, Karnataka Board PUC solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. NCERT solutions for Mathematics Mathematics Part 1 and 2 [English] Class 12 CBSE, Karnataka Board PUC 2 (Inverse Trigonometric Functions) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

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Concepts covered in Mathematics Part 1 and 2 [English] Class 12 chapter 2 Inverse Trigonometric Functions are Properties of Inverse Trigonometric Functions, Basics of Inverse Trigonometric Functions, Domain, Range & Principal Value, Graphs of Inverse Trigonometric Functions, Overview of Inverse Trigonometric Functions, Properties of Inverse Trigonometric Functions, Basics of Inverse Trigonometric Functions, Domain, Range & Principal Value, Graphs of Inverse Trigonometric Functions, Overview of Inverse Trigonometric Functions.

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