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Find the value of the given expression. tan^(–1) (tan (3pi)/4)

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Question

Find the value of the given expression.

`tan^(-1) (tan  (3pi)/4)`

Sum
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Solution

We know that tan–1 (tan x) = x if `x ∈ (-pi/2, pi/2)`, which is the principal value branch of tan1 x.

Here, `(3pi)/4 ∉ ((-pi)/2, pi/2)`.

Now, `tan^(-1) (tan  (3pi)/4)` can be written as: 

`tan^(-1) (tan  (3pi)/4)`

= `tan^(-1) [-tan  ((-3pi)/4)]`

= `tan^(-1) [-tan(pi - pi/4)]`

= `tan^(-1) [-tan  pi/4]`

= `tan^(-1) [tan(-pi/4)]` where `- pi/4 ∈ ((-pi)/2, pi/2)`

∴ `tan^(-1) (tan  (3pi)/4)`

= `tan^(-1) [tan((-pi)/4)]`

= `(-pi)/4`

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Chapter 2: Inverse Trigonometric Functions - EXERCISE 2.2 [Page 30]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 2 Inverse Trigonometric Functions
EXERCISE 2.2 | Q 11. | Page 30

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