English

If cos–1α + cos–1β + cos–1γ = 3π, then α(β + γ) + β(γ + α) + γ(α + β) equals ______.

Advertisements
Advertisements

Question

If cos–1α + cos–1β + cos–1γ = 3π, then α(β + γ) + β(γ + α) + γ(α + β) equals ______.

Options

  • 0

  • 1

  • 6

  • 12

MCQ
Fill in the Blanks
Advertisements

Solution

If cos–1α + cos–1β + cos–1γ = 3π, then α(β + γ) + β(γ + α) + γ(α + β) equals 6.

Explanation:

We have cos–1α + cos–1β + cos–1γ = 3π

⇒ cos–1α + cos–1β + cos–1γ = π + π + π

⇒ cos–1α = π, cos–1β = π and cos–1γ = π

⇒ α = cos π, β = cos π and γ = cos π

∴ α = – 1, β = – 1 and γ = – 1

Which gives α = β = γ = –1

So α(β + γ) + β(γ + α) + γ(α + β)

⇒ (– 1)(– 1 – 1) + (– 1)(– 1 – 1) + (– 1)(– 1 – 1)

⇒ (– 1)(– 2) + (– 1)(– 2) + (– 1)(– 2)

⇒ 2 + 2 + 2

⇒ 6

shaalaa.com
  Is there an error in this question or solution?
Chapter 2: Inverse Trigonometric Functions - Exercise [Page 39]

APPEARS IN

NCERT Exemplar Mathematics Exemplar [English] Class 12
Chapter 2 Inverse Trigonometric Functions
Exercise | Q 35 | Page 39
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×