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Prove that tan^(–1) sqrt(x) = 1/2 cos^(–1) (1 – x)/(1 + x), x ∈ [0, 1].

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Question

Prove that `tan^(-1) sqrt(x) = 1/2 cos^(-1)  (1 - x)/(1 + x), x ∈ [0, 1]`.

Theorem
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Solution

Let x = tan2 θ.

Then, `sqrt(x) = tan θ`

⇒ `θ = tan^(-1) sqrtx`

∴ `(1 - x)/(1 + x) = (1 - tan^2θ)/(1 + tan^2θ)`

= cos 2θ

Now, we have:

R.H.S = `1/2 cos^(-1)  ((1 - x)/(1 + x))`

= `1/2 cos^(-1) (cos 2θ)`

= `1/2 xx 2θ`

= θ

= `tan^(-1) sqrt(x)`

= L.H.S.

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Chapter 2: Inverse Trigonometric Functions - Miscellaneous Exercise on Chapter 2 [Page 31]

APPEARS IN

NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 2 Inverse Trigonometric Functions
Miscellaneous Exercise on Chapter 2 | Q 8. | Page 31

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