English

Prove that: tan^−1 1/5+tan^−1 1/7+tan^−1 1/3+tan^−1 1/8=π/4 - Mathematics

Advertisements
Advertisements

Question

 

Prove that:

`tan^(-1)""1/5+tan^(-1)""1/7+tan^(-1)""1/3+tan^(-1)""1/8=pi/4`

 
Advertisements

Solution

 

LHS:

 `(tan^(-1)""1/5+tan^(-1)""1/7)+(tan^(-1)""1/3+tan^(-1)""1/8)`

`=tan^(-1)((1/5+1/7)/(1-1/5xx1/7))+tan^(-1)((1/3+1/8)/(1-1/3xx1/8)) [:.tan^(-1)A+tan^(-1)B=tan^(-1)((A+B)/(1-AB))] `          

`=tan^(-1)""6/17+tan^(-1)""11/23`

`=tan^(-1)((6/17+11/23)/(1-6/17xx11/23))`

`=tan^(-1)(325/325)`

`=tan^(-1) 1`

`=pi/4`

 
shaalaa.com
  Is there an error in this question or solution?
2015-2016 (March) Delhi Set 1

RELATED QUESTIONS

Write the following function in the simplest form:

`tan^(-1)  (sqrt(1+x^2) -1)/x`, x ≠ 0


Write the function in the simplest form: `tan^(-1)  1/(sqrt(x^2 - 1)), |x| > 1`


if `tan^(-1)  (x-1)/(x - 2) + tan^(-1)  (x + 1)/(x + 2) = pi/4` then find the value of x.


`sin[pi/3 - sin^(-1) (-1/2)]` is equal to ______.


Prove that:

`sin^(-1)  8/17 + sin^(-1)  3/5 = tan^(-1)  77/36`


sin–1 (1 – x) – 2 sin–1 x = `pi/2`, then x is equal to ______.


Solve  `tan^(-1) -  tan^(-1)  (x - y)/(x+y)` is equal to

(A) `pi/2`

(B). `pi/3` 

(C) `pi/4` 

(D) `(-3pi)/4`


Prove that `3sin^(-1)x = sin^(-1) (3x - 4x^3)`, `x in [-1/2, 1/2]`


Solve for x : \[\cos \left( \tan^{- 1} x \right) = \sin \left( \cot^{- 1} \frac{3}{4} \right)\] .


Find the value of `sin^-1[cos(sin^-1 (sqrt(3)/2))]`


Solve: `tan^-1x = cos^-1  (1 - "a"^2)/(1 + "a"^2) - cos^-1  (1 - "b"^2)/(1 + "b"^2), "a" > 0, "b" > 0`


Find the number of solutions of the equation `tan^-1 (x - 1) + tan^-1x + tan^-1(x + 1) = tan^-1(3x)`


Choose the correct alternative:

The equation tan–1x – cot1x = `tan^-1 (1/sqrt(3))` has


Solve the equation `sin^-1 6x + sin^-1 6sqrt(3)x = - pi/2`


Show that `tan(1/2 sin^-1  3/4) = (4 - sqrt(7))/3` and justify why the other value `(4 + sqrt(7))/3` is ignored?


If 3 tan–1x + cot–1x = π, then x equals ______.


If cos–1x > sin–1x, then ______.


The value of cos215° - cos230° + cos245° - cos260° + cos275° is ______.


`"cot" ("cosec"^-1  5/3 + "tan"^-1  2/3) =` ____________.


If x = a sec θ, y = b tan θ, then `("d"^2"y")/("dx"^2)` at θ = `π/6` is:


Simplest form of `tan^-1 ((sqrt(1 + cos "x") + sqrt(1 - cos "x"))/(sqrt(1 + cos "x") - sqrt(1 - cos "x")))`, `π < "x" < (3π)/2` is:


If `"tan"^-1 2  "x + tan"^-1 3  "x" = pi/4`, then x is ____________.


`"sin"^-1 (1/sqrt2)`


The Government of India is planning to fix a hoarding board at the face of a building on the road of a busy market for awareness on COVID-19 protocol. Ram, Robert and Rahim are the three engineers who are working on this project. “A” is considered to be a person viewing the hoarding board 20 metres away from the building, standing at the edge of a pathway nearby. Ram, Robert and Rahim suggested to the firm to place the hoarding board at three different locations namely C, D and E. “C” is at the height of 10 metres from the ground level. For viewer A, the angle of elevation of “D” is double the angle of elevation of “C” The angle of elevation of “E” is triple the angle of elevation of “C” for the same viewer. Look at the figure given and based on the above information answer the following:

𝐴' Is another viewer standing on the same line of observation across the road. If the width of the road is 5 meters, then the difference between ∠CAB and ∠CA'B is ______.


What is the value of cos (sec–1x + cosec–1x), |x| ≥ 1


What is the simplest form of `tan^-1  sqrt(1 - x^2 - 1)/x, x ≠ 0`


If sin–1x + sin–1y + sin–1z = π, show that `x^2 - y^2 - z^2 + 2yzsqrt(1 - x^2) = 0`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×