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Evaluate: tan-13-sec-1(-2).

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Question

Evaluate: `tan^-1 sqrt(3) - sec^-1(-2)`.

Sum
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Solution

`tan^-1 sqrt(3) - sec^-1(-2) = tan^-1 sqrt(3) - [pi - sec^-1 2]`

= `pi/3 - pi + cos^-1(1/2)`

= `- (2pi)/3 + pi/3`

= `- pi/3`.

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Chapter 2: Inverse Trigonometric Functions - Solved Examples [Page 21]

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NCERT Exemplar Mathematics Exemplar [English] Class 12
Chapter 2 Inverse Trigonometric Functions
Solved Examples | Q 6 | Page 21
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