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Find the value of πsin-1[sin(13π7)] - Mathematics

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Question

Find the value of `sin^-1 [sin((13π)/7)]`

Sum
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Solution

`sin^-1 [sin((13π)/7)] = sin^-1 [sin(2π - π/7)]`

= `sin^-1[sin(- π/7)]`

= `- π/7`

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2022-2023 (March) Sample

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