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Evaluate: tan-13-sec-1(-2). - Mathematics

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प्रश्न

Evaluate: `tan^-1 sqrt(3) - sec^-1(-2)`.

योग
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उत्तर

`tan^-1 sqrt(3) - sec^-1(-2) = tan^-1 sqrt(3) - [pi - sec^-1 2]`

= `pi/3 - pi + cos^-1(1/2)`

= `- (2pi)/3 + pi/3`

= `- pi/3`.

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अध्याय 2: Inverse Trigonometric Functions - Solved Examples [पृष्ठ २१]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 2 Inverse Trigonometric Functions
Solved Examples | Q 6 | पृष्ठ २१

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