English

Solve: sin^–1 (x) + sin^–1 (1 – x) = cos^–1 x - Mathematics

Advertisements
Advertisements

Question

Solve:

sin–1 (x) + sin–1 (1 – x) = cos–1 x

Sum
Advertisements

Solution

sin–1 (x) + sin–1 (1 – x) = cos–1 x

⇒ `sin^-1(x) + sin^-1(1 - x) = π/2 - sin^-1x`

⇒ `sin^-1(1 - x) = π/2 - 2sin^-1x`

⇒ `(1 - x) = sin(π/2 - 2sin^-1x)`

⇒ (1 – x) = cos (2 sin–1 x)

⇒ (1 – x) = cos (cos–1 (1 – 2x2))

⇒ (1 – x) = 1 – 2x2

⇒ 2x2 – x = 0

∴ x = `0, 1/2`

shaalaa.com
  Is there an error in this question or solution?
2024-2025 (March) Specimen Paper

RELATED QUESTIONS

 

Prove that:

`tan^(-1)""1/5+tan^(-1)""1/7+tan^(-1)""1/3+tan^(-1)""1/8=pi/4`

 

Prove the following:

3 sin−1 x = sin−1 (3x − 4x3), `x ∈ [-1/2, 1/2]`


Prove `2 tan^(-1)  1/2 + tan^(-1)  1/7 = tan^(-1)  31/17`


`sin[pi/3 - sin^(-1) (-1/2)]` is equal to ______.


Prove that:

`cos^(-1)  4/5 + cos^(-1)  12/13 = cos^(-1)  33/65`


Prove `tan^(-1)   1/5 + tan^(-1)  (1/7) + tan^(-1)  1/3 + tan^(-1)  1/8 = pi/4`


Prove that:

`tan^(-1) sqrtx = 1/2 cos^(-1)  (1-x)/(1+x)`, x ∈ [0, 1]


Prove that:

`cot^(-1)  ((sqrt(1+sin x) + sqrt(1-sinx))/(sqrt(1+sin x) - sqrt(1- sinx))) = x/2, x in (0, pi/4)`


Prove that `tan {pi/4 + 1/2 cos^(-1)  a/b} + tan {pi/4 - 1/2 cos^(-1)  a/b} = (2b)/a`


Solve the following equation for x:  `cos (tan^(-1) x) = sin (cot^(-1)  3/4)`


Solve for x : `tan^-1 ((2-"x")/(2+"x")) = (1)/(2)tan^-1  ("x")/(2), "x">0.`


Find the value of the expression in terms of x, with the help of a reference triangle

`tan(sin^-1(x + 1/2))`


Find the value of `cot[sin^-1  3/5 + sin^-1  4/5]`


Prove that `tan^-1  2/11 + tan^-1  7/24 = tan^-1  1/2`


Choose the correct alternative:

If `cot^-1(sqrt(sin alpha)) + tan^-1(sqrt(sin alpha))` = u, then cos 2u is equal to


Choose the correct alternative:

If `sin^-1x + cot^-1 (1/2) = pi/2`, then x is equal to


Evaluate: `sin^-1 [cos(sin^-1 sqrt(3)/2)]`


Prove that cot–17 + cot–18 + cot–118 = cot–13


If a1, a2, a3,...,an is an arithmetic progression with common difference d, then evaluate the following expression.

`tan[tan^-1("d"/(1 + "a"_1 "a"_2)) + tan^-1("d"/(21 + "a"_2 "a"_3)) + tan^-1("d"/(1 + "a"_3 "a"_4)) + ... + tan^-1("d"/(1 + "a"_("n" - 1) "a""n"))]`


The value of the expression `tan (1/2 cos^-1  2/sqrt(5))` is ______.


The value of cos215° - cos230° + cos245° - cos260° + cos275° is ______.


`"cos" (2  "tan"^-1 1/7) - "sin" (4  "sin"^-1 1/3) =` ____________.


`"tan"^-1 1 + "cos"^-1 ((-1)/2) + "sin"^-1 ((-1)/2)`


The Government of India is planning to fix a hoarding board at the face of a building on the road of a busy market for awareness on COVID-19 protocol. Ram, Robert and Rahim are the three engineers who are working on this project. “A” is considered to be a person viewing the hoarding board 20 metres away from the building, standing at the edge of a pathway nearby. Ram, Robert and Rahim suggested to the firm to place the hoarding board at three different locations namely C, D and E. “C” is at the height of 10 metres from the ground level. For viewer A, the angle of elevation of “D” is double the angle of elevation of “C” The angle of elevation of “E” is triple the angle of elevation of “C” for the same viewer. Look at the figure given and based on the above information answer the following:

Measure of ∠DAB = ________.


What is the simplest form of `tan^-1  sqrt(1 - x^2 - 1)/x, x ≠ 0`


`50tan(3tan^-1(1/2) + 2cos^-1(1/sqrt(5))) + 4sqrt(2) tan(1/2tan^-1(2sqrt(2)))` is equal to ______.


The value of cosec `[sin^-1((-1)/2)] - sec[cos^-1((-1)/2)]` is equal to ______.


Solve for x: `sin^-1(x/2) + cos^-1x = π/6`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×