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Solve the equation sin-16x+sin-163x=-π2 - Mathematics

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Question

Solve the equation `sin^-1 6x + sin^-1 6sqrt(3)x = - pi/2`

Sum
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Solution

From the given equation

we have `sin^-1 6x = - pi/2 - sin^-1 6sqrt(3)x`

⇒ `sin(sin^-1 6x) = sin(- pi/2 - sin^-1 6sqrt(3)x)`

⇒ 6x = `- cos(sin^-1 6sqrt(3)x)`

⇒ 6x = `-sqrt(1 - 108x^2)`.

Squaring, we get

`36x^2= 1 - 108x^2`

⇒ 144x2 = 1

⇒ x = `+- 1/12`

Note that x = `- 1/12` is the only root of the equation as x = `1/12` does not satisfy it.

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Chapter 2: Inverse Trigonometric Functions - Solved Examples [Page 26]

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NCERT Exemplar Mathematics [English] Class 12
Chapter 2 Inverse Trigonometric Functions
Solved Examples | Q 19 | Page 26

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