Advertisements
Advertisements
Question
If `tan^-1x = pi/10` for some x ∈ R, then the value of cot–1x is ______.
Options
`pi/5`
`(2pi)/5`
`(3pi)/5`
`(4pi)/5`
Advertisements
Solution
If `tan^-1x = pi/10` for some x ∈ R, then the value of cot–1x is `(2pi)/5`.
Explanation:
We know tan–1x + cot–1x = `pi/2`.
Therefore cot–1x = `pi/2 - pi/10`
⇒ cot–1x = `pi/2 - pi/10 = (2pi)/5`.
APPEARS IN
RELATED QUESTIONS
If a line makes angles 90°, 60° and θ with x, y and z-axis respectively, where θ is acute, then find θ.
Prove `2 tan^(-1) 1/2 + tan^(-1) 1/7 = tan^(-1) 31/17`
Write the following function in the simplest form:
`tan^(-1) (sqrt(1+x^2) -1)/x`, x ≠ 0
Write the following function in the simplest form:
`tan^(-1) ((3a^2 x - x^3)/(a^3 - 3ax^2)), a > 0; (-a)/sqrt3 < x < a/sqrt3`
Find the value of the following:
`tan^-1 [2 cos (2 sin^-1 1/2)]`
Find the value of the following:
`tan 1/2 [sin^(-1) (2x)/(1+ x^2) + cos^(-1) (1-y^2)/(1+y^2)]`, |x| < 1, y > 0 and xy < 1
Find the value of the given expression.
`tan^(-1) (tan (3pi)/4)`
`cos^(-1) (cos (7pi)/6)` is equal to ______.
Prove that:
`cot^(-1) ((sqrt(1+sin x) + sqrt(1-sinx))/(sqrt(1+sin x) - sqrt(1- sinx))) = x/2, x in (0, pi/4)`
Solve the following equation:
2 tan−1 (cos x) = tan−1 (2 cosec x)
Solve the following equation for x: `cos (tan^(-1) x) = sin (cot^(-1) 3/4)`
Prove that `3sin^(-1)x = sin^(-1) (3x - 4x^3)`, `x in [-1/2, 1/2]`
Solve for x : \[\cos \left( \tan^{- 1} x \right) = \sin \left( \cot^{- 1} \frac{3}{4} \right)\] .
If y = `(x sin^-1 x)/sqrt(1 -x^2)`, prove that: `(1 - x^2)dy/dx = x + y/x`
Find: ∫ sin x · log cos x dx
Solve for x : `tan^-1 ((2-"x")/(2+"x")) = (1)/(2)tan^-1 ("x")/(2), "x">0.`
Find the value of `cot[sin^-1 3/5 + sin^-1 4/5]`
Prove that `tan^-1x + tan^-1 (2x)/(1 - x^2) = tan^-1 (3x - x^3)/(1 - 3x^2), |x| < 1/sqrt(3)`
Simplify: `tan^-1 x/y - tan^-1 (x - y)/(x + y)`
Choose the correct alternative:
`tan^-1 (1/4) + tan^-1 (2/9)` is equal to
Choose the correct alternative:
If |x| ≤ 1, then `2tan^-1x - sin^-1 (2x)/(1 + x^2)` is equal to
Solve the equation `sin^-1 6x + sin^-1 6sqrt(3)x = - pi/2`
If 3 tan–1x + cot–1x = π, then x equals ______.
If `"sec" theta = "x" + 1/(4 "x"), "x" in "R, x" ne 0,`then the value of `"sec" theta + "tan" theta` is ____________.
The value of cot `("cosec"^-1 5/3 + "tan"^-1 2/3)` is ____________.
`"sin" {2 "cos"^-1 ((-3)/5)}` is equal to ____________.
The value of expression 2 `"sec"^-1 2 + "sin"^-1 (1/2)`
The value of the expression tan `(1/2 "cos"^-1 2/sqrt3)`
If tan-1 2x + tan-1 3x = `pi/4,` then x is ____________.
`"cos"^-1 1/2 + 2 "sin"^-1 1/2` is equal to ____________.
`"cos"^-1 (1/2)`
If `"sin"^-1 (1 - "x") - 2 "sin"^-1 ("x") = pi/2,` then x is equal to ____________.
The Government of India is planning to fix a hoarding board at the face of a building on the road of a busy market for awareness on COVID-19 protocol. Ram, Robert and Rahim are the three engineers who are working on this project. “A” is considered to be a person viewing the hoarding board 20 metres away from the building, standing at the edge of a pathway nearby. Ram, Robert and Rahim suggested to the firm to place the hoarding board at three different locations namely C, D and E. “C” is at the height of 10 metres from the ground level. For viewer A, the angle of elevation of “D” is double the angle of elevation of “C” The angle of elevation of “E” is triple the angle of elevation of “C” for the same viewer. Look at the figure given and based on the above information answer the following:

Domain and Range of tan-1 x = ________.
The value of `tan^-1 (x/y) - tan^-1 (x - y)/(x + y)` is equal to
Find the value of `sin^-1 [sin((13π)/7)]`
`tan^-1 sqrt3 - cot^-1 (- sqrt3)` is equal to ______.
