Question

Find the value, if it exists. If not, give the reason for non-existence

`sin^-1 [sin 5]`

Answer 1

`- pi/2 ≤ sin^-1 5 ≤ pi/2`

`- 3   pi/2 ≤ 5 ≤ 2pi`

`- pi/2 ≤ 5 - 2pi ≤ 0 ≤ pi/2`

sin(5 – 2π) = sin 5

sin^–1(sin 5) = 5 – 2π