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NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 chapter 11 - Three Dimensional Geometry [Latest edition]

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Solutions for Chapter 11: Three Dimensional Geometry

Below listed, you can find solutions for Chapter 11 of CBSE, Karnataka Board PUC NCERT for Mathematics Part 1 and 2 [English] Class 12.


Exercise 11.1Exercise 11.2Exercise 11.3Exercise 11.4
Exercise 11.1 [Pages 467 - 478]

NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 11 Three Dimensional Geometry Exercise 11.1 [Pages 467 - 478]

1Page 467

If a line makes angles 90°, 135°, 45° with the x, y and z axes respectively, find its direction cosines.

2Page 467

Find the direction cosines of a line which makes equal angles with the coordinate axes.

3Page 467

If a line has the direction ratios −18, 12, −4, then what are its direction cosines?

4Page 477

Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector `3hati+2hatj-2hatk`.

4Page 467

Show that the points (2, 3, 4), (−1, −2, 1), (5, 8, 7) are collinear.

5Page 477

Find the equation of the line in vector and in Cartesian form that passes through the point with position vector `2hati -hatj+4hatk`  and is in the direction `hati + 2hatj - hatk`.

5Page 467

Find the Direction Cosines of the Sides of the triangle Whose Vertices Are (3, 5, -4), (-1, 1, 2) and (-5, -5, -2).

6Page 477

Find the Cartesian equation of the line which passes through the point (−2, 4, −5) and parallel to the line given by `(x+3)/3 = (y-4)/5 = (z+8)/6`.

7Page 477

The Cartesian equation of a line is `(x-5)/3 = (y+4)/7 = (z-6)/2` Write its vector form.

8Page 477

Find the vector and the Cartesian equations of the lines that pass through the origin and (5, −2, 3).

9Page 478

Find the vector and the Cartesian equations of the line that passes through the points (3, −2, −5), (3, −2, 6).

 

Exercise 11.2 [Pages 477 - 478]

NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 11 Three Dimensional Geometry Exercise 11.2 [Pages 477 - 478]

1Page 477

Show that the three lines with direction cosines `12/13, (-3)/13, (-4)/13;  4/13, 12/13, 3/13;  3/13, (-4)/13, 12/13 ` are mutually perpendicular.

2Page 477

Show that the line through the points (1, −1, 2) (3, 4, −2) is perpendicular to the line through the points (0, 3, 2) and (3, 5, 6).

3Page 477

Show that the line through the points (4, 7, 8) (2, 3, 4) is parallel to the line through the points (−1, −2, 1), (1, 2, 5).

10.1Page 478

Find the angle between the following pair of lines:

`vecr = 2hati - 5hatj + hatk + lambda(3hati - 2hatj + 6hatk) and vecr = 7hati - 6hatk + mu(hati + 2hatj + 2hatk)`

10.2Page 478

Find the angle between the following pair of lines:

`vecr = 3hati + hatj - 2hatk + lambda(hati - hatj - 2hatk) and vecr = 2hati - hatj -56hatk + mu(3hati - 5hatj - 4hatk)`

11.1Page 478

Find the angle between the following pairs of lines: 

`(x-2)/2 = (y-1)/5 = (z+3)/(-3)` and `(x+2)/(-1) = (y-4)/8 = (z -5)/4`

11.2Page 478

Find the angle between the following pairs of lines:

`x/y = y/2 = z/1` and `(x-5)/4 = (y-2)/1 = (z - 3)/8`

12Page 478

Find the values of p so the line `(1-x)/3 = (7y-14)/2p = (z-3)/2` and `(7-7x)/(3p) = (y -5)/1 = (6-z)/5` are at right angles.

13Page 478

Show that the lines `(x-5)/7 = (y + 2)/(-5) = z/1` and `x/1 = y/2 = z/3` are perpendicular to each other.

14Page 478

Find the shortest distance between the lines: 

`vecr = (hati+2hatj+hatk) + lambda(hati-hatj+hatk)` and `vecr = 2hati - hatj - hatk + mu(2hati + hatj + 2hatk)`

15Page 478

Find the shortest distance between the lines.

`(x + 1)/7 = (y + 1)/(- 6) = (z + 1)/1` and `(x - 3)/1 = (y - 5)/(- 2) = (z - 7)/1`.

16Page 478

Find the shortest distance between the lines whose vector equations are `vecr = (hati + 2hatj + 3hatk) + lambda(hati - 3hatj + 2hatk)` and `vecr = 4hati + 5hatj + 6hatk + mu(2hati + 3hatj + hatk)`.

17Page 478

Find the shortest distance between the lines whose vector equations are `vecr = (1-t)hati + (t - 2)hatj + (3 -2t)hatk` and `vecr = (s+1)hati + (2s + 1)hatk`.

Exercise 11.3 [Pages 493 - 494]

NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 11 Three Dimensional Geometry Exercise 11.3 [Pages 493 - 494]

1Page 493

In following cases, determine the direction cosines of the normal to the plane and the distance from the origin.

z = 2

1.2Page 493

In following cases, determine the direction cosines of the normal to the plane and the distance from the origin.

x + y + z = 1

1.3Page 493

In following cases, determine the direction cosines of the normal to the plane and the distance from the origin.

2x + 3y – z = 5

1.4Page 493

In following cases, determine the direction cosines of the normal to the plane and the distance from the origin.

5y + 8 = 0

2Page 493

Find the vector equation of a plane which is at a distance of 7 units from the origin and normal to the vector.`3hati + 5hatj - 6hatk`

3Page 493

In the following cases, find the coordinates of the foot of the perpendicular drawn from the origin.

x + y + z = 1

3.1Page 493

Find the Cartesian equation of the following planes:

`vecr.(hati + hatj-hatk) = 2`

3.2Page 493

Find the Cartesian equation of the following planes:

`vecr.(2hati + 3hatj-4hatk) = 1`

3.3Page 493

Find the Cartesian equation of the following planes:

`vecr.[(s-2t)hati + (3 - t)hatj + (2s + t)hatk] = 15`

4.1Page 493

In the following cases, find the coordinates of the foot of the perpendicular drawn from the origin.

2x + 3y + 4z – 12 = 0

4.2Page 493

In the following cases, find the coordinates of the foot of the perpendicular drawn from the origin.

3y + 4z – 6 = 0

4.4Page 493

In the following cases, find the coordinates of the foot of the perpendicular drawn from the origin.

5y + 8 = 0

5.1Page 493

Find the vector and Cartesian equation of the planes that passes through the point (1, 0, −2) and the normal to the plane is `hati + hatj - hatk`

5.2Page 493

Find the vector and Cartesian equation of the planes that passes through the point (1, 4, 6) and the normal vector to the plane is `hati -2hatj +  hatk`

6.1Page 493

Find the equations of the planes that passes through three points.

(1, 1, −1), (6, 4, −5), (−4, −2, 3)

6.2Page 493

Find the equations of the planes that passes through three points.

(1, 1, 0), (1, 2, 1), (−2, 2, −1)

7Page 493

Find the intercepts cut off by the plane 2x + y – z = 5.

8Page 493

Find the equation of the plane with intercept 3 on the y-axis and parallel to ZOX plane.

9Page 493

Find the equation of the plane through the intersection of the planes 3x – y + 2z – 4 = 0 and x + y + z – 2 = 0 and the point (2, 2, 1).

10Page 493

Find the vector equation of the plane passing through the intersection of the planes `vecr.(2hati + 2hatj - 3hatk) = 7, vecr.(2hati + 5hatj + 3hatk) = 9` and through the point (2, 1, 3)

11Page 493

Find the equation of the plane through the line of intersection of the planes x + y + z = 1 and 2x + 3y + 4z = 5 which is perpendicular to the plane x − y + z = 0. Also find the distance of the plane, obtained above, from the origin.

12Page 494

Find the angle between the planes whose vector equations are `vecr.(2hati + 2hatj - 3hatk) = 5 and hatr.(3hati - 3hatj  + 5hatk) = 3`

13.1Page 494

In the following cases, determine whether the given planes are parallel or perpendicular, and in case they are neither, find the angles between them.

7x + 5y + 6z + 30 = 0 and 3x – y – 10z + 4 = 0

13.2Page 494

In the following cases, determine whether the given planes are parallel or perpendicular, and in case they are neither, find the angles between them.

2x + y + 3z – 2 = 0 and x – 2y + 5 = 0

 

13.3Page 494

In the following cases, determine whether the given planes are parallel or perpendicular, and in case they are neither, find the angles between them.

2x – 2y + 4z + 5 = 0 and 3x – 3y + 6z – 1 = 0

13.4Page 494

In the following cases, determine whether the given planes are parallel or perpendicular, and in case they are neither, find the angles between them.

2x – y + 3z – 1 = 0 and 2x – y + 3z + 3 = 0

13.5Page 494

In the following cases, determine whether the given planes are parallel or perpendicular, and in case they are neither, find the angles between them.

4x + 8y + z – 8 = 0 and y + z – 4 = 0

14.1Page 494

In the given cases, find the distance of each of the given points from the corresponding given plane.

Point                    Plane
(0, 0, 0)           3x – 4y + 12 z = 3

14.2Page 494

In the given cases, find the distance of each of the given points from the corresponding given plane

Point                   Plane

(3, – 2, 1)             2x – y + 2z + 3 = 0

14.3Page 494

In the given cases, find the distance of each of the given points from the corresponding given plane.

Point                 Plane

(2, 3, – 5)           x + 2y – 2z = 9

14.4Page 494

In the given cases, find the distance of each of the given points from the corresponding given plane.

Point              Plane

(– 6, 0, 0)        2x – 3y + 6z – 2 = 0

Exercise 11.4 [Pages 497 - 499]

NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 11 Three Dimensional Geometry Exercise 11.4 [Pages 497 - 499]

1Page 497

Show that the line joining the origin to the point (2, 1, 1) is perpendicular to the line determined by the points (3, 5, – 1), (4, 3, – 1).

2Page 497

If l1m1n1 and l2m2n2 are the direction cosines of two mutually perpendicular lines, show that the direction cosines of the line perpendicular to both of these are m1n2 − m2n1n1l2 − n2l1l1m2 ­− l2m1.

3Page 498

Find the angle between the lines whose direction ratios are a, b, c and b − c, c − a, a − b.

4Page 498

Find the equation of a line parallel to x-axis and passing through the origin.

5Page 498

If the coordinates of the points A, B, C, D be (1, 2, 3), (4, 5, 7), (­−4, 3, −6) and (2, 9, 2) respectively, then find the angle between the lines AB and CD.

6Page 498

If the lines `(x-1)/(-3) = (y -2)/(2k) = (z-3)/2 and (x-1)/(3k) = (y-1)/1 = (z -6)/(-5)` are perpendicular, find the value of k.

7Page 498

Find the vector equation of the plane passing through (1, 2, 3) and perpendicular to the plane `vecr.(hati + 2hatj -5hatk) + 9 = 0`

8Page 498

Find the equation of the plane passing through (abc) and parallel to the plane `vecr.(hati + hatj + hatk) = 2`

9Page 498

Find the shortest distance between lines `vecr = 6hati + 2hatj + 2hatk + lambda(hati - 2hatj + 2hatk)` and `vecr =-4hati - hatk + mu(3hati - 2hatj - 2hatk)`.

10Page 498

Find the coordinates of the point where the line through (5, 1, 6) and (3, 4, 1) crosses the YZ-plane

11Page 498

Find the coordinates of the point where the line through (5, 1, 6) and (3, 4, 1) crosses the ZX − plane.

12Page 498

Find the coordinates of the point where the line through (3, ­−4, −5) and (2, − 3, 1) crosses the plane 2x + z = 7).

13Page 498

Find the equation of the plane passing through the point (−1, 3, 2) and perpendicular to each of the planes x + 2+ 3z = 5 and 3x + 3z = 0.

14Page 498

If the points (1, 1, p) and (−3, 0, 1) be equidistant from the plane `vecr.(3hati + 4hatj - 12hatk)+ 13 = 0`, then find the value of p.

15Page 498

Find the equation of the plane passing through the line of intersection of the planes `vecr.(hati + hatj + hatk) = 1` and `vecr.(2hati + 3hatj -hatk) + 4 = 0` and parallel to x-axis.

16Page 498

If O be the origin and the coordinates of P be (1, 2, −3), then find the equation of the plane passing through P and perpendicular to OP.

17Page 498

Find the equation of the plane which contains the line of intersection of the planes `vecrr.(hati + 2hatj + 3hatk) - 4 = 0, vecr.(2hati + htj - hatk) + 5 = 0`,  and which is perpendicular to the plane `vecr.(5hati + 3hatj - 6hatk) + 8 = 0`.

18Page 499

Find the distance of the point (−1, −5, −­10) from the point of intersection of the line `vecr = 2hati -hatj + 2hatk + lambda(3hati + 4hatj + 2hatk)` and the plane `vecr.(hati -hatj + hatk) = 5`.

19Page 499

Find the vector equation of the line passing through (1, 2, 3) and parallel to the planes `vecr = (hati - hatj + 2hatk)  = 5`and `vecr.(3hati + hatj + hatk) = 6`

20Page 499

Find the vector equation of the line passing through the point (1, 2, − 4) and perpendicular to the two lines: 

`(x -8)/3 = (y+19)/(-16) = (z - 10)/7 and (x - 15)/3 = (y - 29)/8 = (z- 5)/(-5)`

21Page 499

Prove that if a plane has the intercepts abc and is at a distance of P units from the origin, then `1/a^2 + 1/b^2 + 1/c^2 = 1/p^2`

22Page 499

Distance between the two planes: 2x + 3y + 4z = 4 and 4x + 6y + 8z = 12 is

(A) 2 units

(B) 4 units

(C) 8 units

(D)`2/sqrt29 "units"`

23Page 499

The planes: 2− y + 4z = 5 and 5x − 2.5y + 10z = 6 are

(A) Perpendicular

(B) Parallel

(C) intersect y-axis

(C) passes through `(0,0,5/4)`

Solutions for 11: Three Dimensional Geometry

Exercise 11.1Exercise 11.2Exercise 11.3Exercise 11.4

NCERT solutions for Mathematics Part 1 and 2 [English] Class 12 chapter 11 - Three Dimensional Geometry

Shaalaa.com has the CBSE, Karnataka Board PUC Mathematics Mathematics Part 1 and 2 [English] Class 12 CBSE, Karnataka Board PUC solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. NCERT solutions for Mathematics Mathematics Part 1 and 2 [English] Class 12 CBSE, Karnataka Board PUC 11 (Three Dimensional Geometry) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. NCERT textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Mathematics Part 1 and 2 [English] Class 12 chapter 11 Three Dimensional Geometry are Introduction of Three Dimensional Geometry, Angle Between Two Lines, Equation of a Plane in Normal Form, Equation of a Plane Perpendicular to a Given Vector and Passing Through a Given Point, Direction Cosines and Direction Ratios of a Line, Equation of a Line in Space, Shortest Distance Between Two Lines, Overview of Three Dimensional Geometry, Distance of a Point from a Plane, Angle Between Line and a Plane, Angle Between Two Planes, Vector and Cartesian Equation of a Plane, Relation Between Direction Ratio and Direction Cosines, Three - Dimensional Geometry Examples and Solutions, Equation of a Plane Passing Through Three Non Collinear Points, Coplanarity of Two Lines, Equations of Line in Different Forms, Plane Passing Through the Intersection of Two Given Planes, Introduction of Three Dimensional Geometry, Angle Between Two Lines, Equation of a Plane in Normal Form, Equation of a Plane Perpendicular to a Given Vector and Passing Through a Given Point, Direction Cosines and Direction Ratios of a Line, Equation of a Line in Space, Shortest Distance Between Two Lines, Overview of Three Dimensional Geometry, Distance of a Point from a Plane, Angle Between Line and a Plane, Angle Between Two Planes, Vector and Cartesian Equation of a Plane, Relation Between Direction Ratio and Direction Cosines, Three - Dimensional Geometry Examples and Solutions, Equation of a Plane Passing Through Three Non Collinear Points, Coplanarity of Two Lines, Equations of Line in Different Forms, Plane Passing Through the Intersection of Two Given Planes.

Using NCERT Mathematics Part 1 and 2 [English] Class 12 solutions Three Dimensional Geometry exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in NCERT Solutions are essential questions that can be asked in the final exam. Maximum CBSE, Karnataka Board PUC Mathematics Part 1 and 2 [English] Class 12 students prefer NCERT Textbook Solutions to score more in exams.

Get the free view of Chapter 11, Three Dimensional Geometry Mathematics Part 1 and 2 [English] Class 12 additional questions for Mathematics Mathematics Part 1 and 2 [English] Class 12 CBSE, Karnataka Board PUC, and you can use Shaalaa.com to keep it handy for your exam preparation.

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