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The Cartesian equation of a line is x-53=y+47=z-62 Write its vector form.

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Question

The Cartesian equation of a line is `(x-5)/3 = (y+4)/7 = (z-6)/2` Write its vector form.

Sum
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Solution

The equation of the line is `(x - 5)/3 = (y + 4)/7 = (z - 6)/2`.

This line passes through the point (5, −4, 6) and its direction ratios are 3, 7, 2.

That is, `vec(r_1) = 5hati - 4hatj + 6hatk` and `vecb = 3hati + 7hatj + 2hatk`

Hence the vector equation of the line is `vecr = vec(r_1) + λ vecb`

= `(5hati - 4hatj + 6hatk) + λ(3hati + 7hatj + 2hatk)`

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Chapter 11: Three Dimensional Geometry - Exercise 11.1 [Page 477]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 11 Three Dimensional Geometry
Exercise 11.1 | Q 7 | Page 477

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