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Find the Angle Between Two Lines, One of Which Has Direction Ratios 2, 2, 1 While the Other One is Obtained by Joining the Points (3, 1, 4) and (7, 2, 12). - Mathematics

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Question

Find the angle between two lines, one of which has direction ratios 2, 2, 1 while the  other one is obtained by joining the points (3, 1, 4) and (7, 2, 12). 

Sum
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Solution

The direction ratios of the line joining the points (3, 1, 4) and (7, 2, 12) are proportional to 4, 1, 8.

Let

\[\overrightarrow{m_1} \text{ and } \overrightarrow{m_2}\]  be vectors parallel to the lines having direction ratios proportional to 2, 2, 1 and 4, 1, 8.

Now, 

\[\overrightarrow{b_1} = 2 \hat{i} + 2 \hat{j}  + \hat{k}  \]

\[ \overrightarrow{b_2} = 4 \hat{i}  + \hat{j} + 8 \hat{k} \]

If θ is the angle between the given lines, then 

\[\cos \theta = \frac{\overrightarrow{m_1} . \overrightarrow{m_2}}{\left| \overrightarrow{m_1} \right| \left| \overrightarrow{m_2} \right|}\]

\[ = \frac{\left( 2 \hat{i} + 2 \hat{j} + \hat{k}  \right) . \left( 4 \hat{i}  + \hat{j}  + 8 \hat{k}  \right)}{\sqrt{2^2 + 2^2 + 1^2} \sqrt{4^2 + 1^2 + 8^2}}\]

\[ = \frac{8 + 2 + 8}{3 \times 9}\]

\[ = \frac{2}{3}\]

\[ \Rightarrow \theta = \cos^{- 1} \left( \frac{2}{3} \right)\]

 

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Chapter 28: Straight Line in Space - Exercise 28.2 [Page 16]

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RD Sharma Mathematics [English] Class 12
Chapter 28 Straight Line in Space
Exercise 28.2 | Q 11 | Page 16

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