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The Cartestation Equation of Line Is (x-6)/2=(y+4)/7=(z-5)/3 Find Its Vector Equation.

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Question

The Cartestation equation of  line is `(x-6)/2=(y+4)/7=(z-5)/3` find its vector equation.

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Solution

`(x-6)/2=(y+4)/7=(z-5)/3`

Line is passing through the point (6,–4,5) with drs 2, 7, 3

Equation of line in vector form is

`vecr=(6veci-4vecj+5veck)+lambda(2 veci+7 vecj+3vec k)`

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2013-2014 (March)

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