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Show that the Lines X − 1 3 = Y + 1 2 = Z − 1 5 a N D X + 2 4 = Y − 1 3 = Z + 1 − 2 Do Not Intersect.

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Question

Show that the lines \[\frac{x - 1}{3} = \frac{y + 1}{2} = \frac{z - 1}{5} \text{           and                } \frac{x + 2}{4} = \frac{y - 1}{3} = \frac{z + 1}{- 2}\]  do not intersect. 

Sum
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Solution

The coordinates of any point on the first line are given by 

\[\frac{x - 1}{3} = \frac{y + 1}{2} = \frac{z - 1}{5} = \lambda\]

\[ \Rightarrow x = 3\lambda + 1\]

\[ y = 2\lambda - 1 \]

\[ z = 5\lambda + 1\]

The coordinates of a general point on the first line are 

\[\left( 3\lambda + 1, 2\lambda - 1, 5\lambda + 1 \right)\] 

The coordinates of any point on the second line are given by 

\[\frac{x + 2}{4} = \frac{y - 1}{3} = \frac{z + 1}{- 2} = \mu\]

\[ \Rightarrow x = 4\mu - 2\]

\[ y = 3\mu + 1 \]

\[ z = - 2\mu - 1\]

The coordinates of a general point on the second line are 

\[\left( 4\mu - 2, 3\mu + 1, - 2\mu - 1 \right)\] 

If the lines intersect, then they have a common point. So, for some values of  \[\lambda \text{ and }  \mu\]   

we must have 

\[3\lambda + 1 = 4\mu - 2, 2\lambda - 1 = 3\mu + 1, 5\lambda + 1 = - 2\mu - 1\]

\[ \Rightarrow 3\lambda - 4\mu = - 3 . . . (1)\]

\[ 2\lambda - 3\mu = 2 . . . (2)\]

\[ 5\lambda + 2\mu = - 2 . . . (3)\]

\[\text{ Solving (1) and (2), we get } \]

\[\lambda = - 17 \]

\[\mu = - 12\]

\[\text{ Substituting } \lambda = - 17 \text{ and }  \mu = - 12 \text{ in (3), we get } \]

\[LHS = 3\lambda + 2\mu\]

\[ = 3\left( - 17 \right) + 2\left( - 12 \right)\]

\[ = - 75\]

\[ \neq - 2\]

\[ \Rightarrow LHS \neq RHS\]

\[\text{ Hence, the given lines do not intersect } .\]

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Chapter 27: Straight Line in Space - Exercise 28.3 [Page 22]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 27 Straight Line in Space
Exercise 28.3 | Q 2 | Page 22

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