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Find the Shortest Distance Between the Following Pairs of Lines Whose Vector : → R = 3 ^ I + 8 ^ J + 3 ^ K + λ ( 3 ^ I − ^ J + ^ K ) and → R = − 3 ^ I − 7 ^ J + 6 ^ K + μ ( − 3 ^ I + 2 ^ J + 4 ^ K ) - Mathematics

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Question

Find the shortest distance between the following pairs of lines whose vector equations are: \[\vec{r} = 3 \hat{i} + 8 \hat{j} + 3 \hat{k}  + \lambda\left( 3 \hat{i}  - \hat{j}  + \hat{k}  \right) \text{ and }  \vec{r} = - 3 \hat{i}  - 7 \hat{j}  + 6 \hat{k}  + \mu\left( - 3 \hat{i}  + 2 \hat{j}  + 4 \hat{k} \right)\]

Sum
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Solution

\[\vec{r} = 3 \hat{i}  + 8 \hat{j} + 3 \hat{k} + \lambda\left( 3 \hat{i} - \hat{j} + \hat{k} \right) \text{ and } \vec{r} = - 3 \hat{i} - 7 \hat{j} + 6 \hat{k} + \mu\left( - 3 \hat{i} + 2 \hat{j} + 4 \hat{k} \right)\]  Comparing the given equations with the equations

\[\vec{r} = \vec{a_1} + \lambda \vec{b_1} \text{ and }  \vec{r} = \vec{a_2} + \mu \vec{b_2}\]

\[\vec{a_1} = 3 \hat{i} + 8 \hat{j} + 3 \hat{k} \]

\[ \vec{a_2} = - 3 \hat{i} - 7 \hat{j} + 6 \hat{k} \]

\[ \vec{b_1} = 3 \hat{i} - \hat{j} + \hat{k}  \]

\[ \vec{b_2} = - 3 \hat{i}  + 2 \hat{j}  + 4 \hat{k}  \]

\[ \therefore \vec{a_2} - \vec{a_1} = - 6 \hat{i}  - 15 \hat{j}  + 3 \hat{k} \]

\[and \vec{b_1} \times \vec{b_2} = \begin{vmatrix}\hat{i} & \hat{j} & \hat{k} \\ 3 & - 1 & 1 \\ - 3 & 2 & 4\end{vmatrix}\]

\[ = - 6 \hat{i} - 15 \hat{j} + 3 \hat{k} \]

\[ \Rightarrow \left| \vec{b_1} \times \vec{b_2} \right| = \sqrt{\left( - 6 \right)^2 + \left( - 15 \right)^2 + 3^2}\]

\[ = \sqrt{36 + 225 + 9}\]

\[ = \sqrt{270}\]

\[\left( \vec{a_2} - \vec{a_1} \right) . \left( \vec{b_1} \times \vec{b_2} \right) = \left( - 6 \hat{i} - 15 \hat{j} + 3 \hat{k} \right) . \left( - 6 \hat{i} - 15 \hat{j} + 3 \hat{k} \right)\]

\[ = 36 + 225 + 9\]

\[ = 270\]

The shortest distance between the lines

\[\vec{r} = \vec{a_1} + \lambda \vec{b_1} \text{ and } \vec{r} = \vec{a_2} + \mu \vec{b_2}\] is given by

\[d = \left| \frac{\left( \vec{a_2} - \vec{a_1} \right) . \left( \vec{b_1} \times \vec{b_2} \right)}{\left| \vec{b_1} \times \vec{b_2} \right|} \right|\]

\[ = \frac{270}{\sqrt{270}}\]

\[ = \sqrt{270}\]

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Chapter 28: Straight Line in Space - Exercise 28.5 [Page 37]

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RD Sharma Mathematics [English] Class 12
Chapter 28 Straight Line in Space
Exercise 28.5 | Q 1.1 | Page 37

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