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If the Lines X − 1 − 3 = Y − 2 2 λ = Z − 3 2 a N D X − 1 3 λ = Y − 1 1 = Z − 6 − 5 Are Perpendicular, Find the Value of λ.

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Question

If the lines \[\frac{x - 1}{- 3} = \frac{y - 2}{2 \lambda} = \frac{z - 3}{2} \text{     and     } \frac{x - 1}{3\lambda} = \frac{y - 1}{1} = \frac{z - 6}{- 5}\]  are perpendicular, find the value of λ.

Sum
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Solution

The equations of the given lines are 

\[\frac{x - 1}{- 3} = \frac{y - 2}{2 \lambda} = \frac{z - 3}{2}\]

\[\frac{x - 1}{3\lambda} = \frac{y - 1}{1} = \frac{z - 6}{- 5}\]

Since the given lines are perpendicular to each other, we have 

\[- 3\left( 3\lambda \right) + 2\lambda\left( 1 \right) + 2\left( - 5 \right) = 0\]

\[ \Rightarrow - 9\lambda + 2\lambda - 10 = 0\]

\[ \Rightarrow \lambda = - \frac{10}{7}\]

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Chapter 27: Straight Line in Space - Exercise 28.2 [Page 17]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 27 Straight Line in Space
Exercise 28.2 | Q 21 | Page 17

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