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Question
Find the cartesian equation of a line passing through (1, −1, 2) and parallel to the line whose equations are \[\frac{x - 3}{1} = \frac{y - 1}{2} = \frac{z + 1}{- 2}\] Also, reduce the equation obtained in vector form.
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Solution
We know that the cartesian equation of a line passing through a point with position vector `vec a ` and parallel to the vector `vec m ` is \[\frac{x - x_1}{a} = \frac{y - y_2}{b} = \frac{z - z_3}{c}\]
Here,
\[\vec{a} = x_1 \hat{i} + y_1 \hat{j} + z_1 \hat{k} \]
\[ \vec{m} = a \hat{i} + b \hat{j} + c \hat{k} \]
Here, \[\vec{a} = \hat{i} - \hat{j} + 2 \hat{k} \text{ and } \vec{b} = \hat{i} + 2 \hat{j} - 2 \hat{k}\]
Cartesian equation of the required line is
\[\frac{x - 1}{1} = \frac{y - \left( - 1 \right)}{2} = \frac{z - 2}{- 2}\]
\[ \Rightarrow \frac{x - 1}{1} = \frac{y + 1}{2} = \frac{z - 2}{- 2}\]
We know that the cartesian equation of a line passing through a point with position vector `vec a` and parallel to the vector `vec m` is \[\vec{r} = \vec{a} + \lambda \vec{m}\]
Here, the line is passing through the point (1,1,-2) and its direction ratios are proportional to 1, 2, -2 .
Vector equation of the required line is
\[\vec{r} = \left( \hat{i} - \hat{j} + 2 \hat{k} \right) + \lambda\left( \hat{i} + 2 \hat{j} - 2 \hat{k} \right)\]
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A line passes through the point (2, – 1, 3) and is perpendicular to the lines `vecr = (hati + hatj - hatk) + λ(2hati - 2hatj + hatk)` and `vecr = (2hati - hatj - 3hatk) + μ(hati + 2hatj + 2hatk)` obtain its equation.
