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Find the Equation of the Line Passing Through the Point (2, −1, 3) and Parallel to the Line → R = ( ^ I − 2 ^ J + ^ K ) + λ ( 2 ^ I + 3 ^ J − 5 ^ K ) . - Mathematics

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Question

Find the equation of the line passing through the point (2, −1, 3) and parallel to the line  \[\overrightarrow{r} = \left( \hat{i} - 2 \hat{j} + \hat{k} \right) + \lambda\left( 2 \hat{i} + 3 \hat{j} - 5 \hat{k} \right) .\]

Sum
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Solution

The given line is parallel to the vector  \[2 \hat{i} + 3 \hat{j} - 5 \hat{k} \] and the required line is parallel to the given line. So, the required line is parallel to the vector \[2 \hat{i} + 3 \hat{j} - 5 \hat{k} \]  Hence, the equation of the required line passing through the point (2,-1, 3) and parallel to the vector  \[2 \hat{i} + 3 \hat{j} - 5 \hat{k} \]  is  \[\overrightarrow{r} = \left( 2 \hat{i} - \hat{j} + 3 \hat{k} \right) + \lambda\left( 2 \hat{i} + 3 \hat{j} - 5 \hat{k} \right)\] 

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Chapter 28: Straight Line in Space - Exercise 28.2 [Page 16]

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RD Sharma Mathematics [English] Class 12
Chapter 28 Straight Line in Space
Exercise 28.2 | Q 14 | Page 16

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A line passes through the point (2, – 1, 3) and is perpendicular to the lines `vecr = (hati + hatj - hatk) + λ(2hati - 2hatj + hatk)` and `vecr = (2hati - hatj - 3hatk) + μ(hati + 2hatj + 2hatk)` obtain its equation.


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