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Find the vector and Cartesian equations of the line through the point (1, 2, −4) and perpendicular to the two lines.

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Question

Find the vector and Cartesian equations of the line through the point (1, 2, −4) and perpendicular to the two lines. 

`vecr=(8hati-19hatj+10hatk)+lambda(3hati-16hatj+7hatk) " and "vecr=(15hati+29hatj+5hatk)+mu(3hati+8hatj-5hatk)`

 

 

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Solution

The equations of the given lines are

`vecr=(8hati-19hatj+10hatk)+lambda(3hati-16hatj+7hatk) " ...(1)"`

`vecr=(15hati+29hatj+5hatk)+mu(3hati+8hatj-5hatk) " .....(2)"`

Normal parallel to (1) is `vec(n_1)=3hati-16hatj+7hatk`

Normal parallel to (2) is `vec(n_2)=3hati+8hatj-5hatk`

The required line is perpendicular to the given lines. So, the normal n⃗  parallel to the required line is perpendicular to `vec(n_1) " and "vec(n_2)`

`:.vecn=vec(n_1)xxvec(n_2)=|(hati, hatj,hatk),(3,-16,7),(3,8,-5)|=24hati+36hatj+72hatk`

Thus, the vector equation of the required line is

`vecr=(hati+2hatj-4hatk)+gamma(24hati+36hatj+72hatk)`

`=>vecr=(hati+2hatj-4hatk)+k(2hati+3hatj+6hatk) " (Where k=12γ)"`

Also, the Cartesian equation of the required line is

`(x-1)/2=(y-2)/3=(z+4)/6`

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2015-2016 (March) Delhi Set 1

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