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The Straight Line X − 3 3 = Y − 2 1 = Z − 1 0 (A) Parallel to X-axis (B) Parallel to Y-axis (C) Parallel to Z-axis (D) Perpendicular to Z-axis

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Question

The straight line \[\frac{x - 3}{3} = \frac{y - 2}{1} = \frac{z - 1}{0}\] is

Options

  •  parallel to x-axis

  •  parallel to y-axis 

  •  parallel to z-axis 

  •  perpendicular to z-axis

     
MCQ
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Solution

 perpendicular to z-axis

We have , 

\[\frac{x - 3}{3} = \frac{y - 2}{1} = \frac{z - 1}{0}\] 

Also, the given line is parallel to the vector \[\vec{b} = 3 \hat{i}  + \hat{j}  + 0 \hat{k} \]

Let 

\[x \hat{i}  + y \hat{j} + z \hat{k} \]  be perpendicular to the given line.
Now,

\[3x + 4y + 0z = 0\] 

It is satisfied by the coordinates of z-axis, i.e.

(0, 0, 1).

Hence, the given line is perpendicular to z-axis. 

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Chapter 27: Straight Line in Space - MCQ [Page 43]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 27 Straight Line in Space
MCQ | Q 13 | Page 43

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