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Question
In the given cases, find the distance of each of the given points from the corresponding given plane
Point Plane
(3, – 2, 1) 2x – y + 2z + 3 = 0
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Solution
It is known that the distance between a point, p(x1, y1, z1), and a plane, Ax + By + Cz = D, is given by,
The given point is (3, − 2, 1) and the plane is 2x – y + 2z + 3 = 0
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