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Question
Find the Cartesian equation of the following planes:
`vecr.(2hati + 3hatj-4hatk) = 1`
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Solution
`vecr.(2hati + 3hatj-4hatk)` = 1 ....(1)
For any arbitrary point P (x, y, z) on the plane, position vector `vecr` is given by,`vecr = xhati + yhatj - zhatk`
Substituting the value of `vecr` in equation (1), we obtain
This is the Cartesian equation of the plane.
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