मराठी

Find the Cartesian equation of the following planes: vecr.(2hati + 3hatj-4hatk) = 1

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प्रश्न

Find the Cartesian equation of the following planes:

`vecr.(2hati + 3hatj-4hatk) = 1`

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उत्तर

`vecr.(2hati + 3hatj-4hatk)` = 1  ....(1)

For any arbitrary point P (xyz) on the plane, position vector `vecr` is given by,`vecr = xhati + yhatj - zhatk`

Substituting the value of `vecr` in equation (1), we obtain

This is the Cartesian equation of the plane.

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पाठ 11: Three Dimensional Geometry - Exercise 11.3 [पृष्ठ ४९३]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 11 Three Dimensional Geometry
Exercise 11.3 | Q 3.2 | पृष्ठ ४९३
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