Question

Distance between the two planes: 2x + 3y + 4z = 4 and 4x + 6y + 8z = 12 is

(A) 2 units

(B) 4 units

(C) 8 units

(D)`2/sqrt29 "units"`

Answer 1

The equations of the planes are

2x + 3y + 4z = 4  ....(1)

4x + 6y + 8z = 12

`=> 2x + 3y + 4z = 6 ...(2)`

It can be seen that the given planes are parallel.

It is known that the distance between two parallel planes, ax + by + cz = d₁ and ax + by+ cz = d₂, is given by,

Thus, the distance between the lines `2/sqrt29`  units.

Hence, the correct answer is D.