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Question
Find `bb(dy/dx)` in the following:
2x + 3y = sin y
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Solution
2x + 3y = sin y
Differentiating both sides for x,
⇒ `2 d/dx (x) + 3 d/dx (y) = d/dx(sin y)`
⇒ `2 xx 1 + 3 dy/dx = cos y`
⇒ `2 = cos y dy/dx - 3 dy/dx`
⇒ `2 = dy/dx (cos y - 3)`
∴ `dy/dx = 2/(cos y - 3)`
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