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Question
Differentiate the following w.r.t. x:
log (log x), x > 1
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Solution
Let, y = log (log x)
Differentiating both sides with respect to x,
`dy/dx = d/dx log (log x)`
= `1/(log x) d/dx log x`
= `1/(log x) * 1/x`
= `1/(x log x)`, x > 1
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