English

Differentiate the function with respect to x: sin3 x + cos6 x

Advertisements
Advertisements

Question

Differentiate the function with respect to x:

sin3 x + cos6 x

Sum
Advertisements

Solution

Let, y = sin3 x + cos6 x

On differentiating with respect to x,

`dy/dx = d/dx sin^3 x + d/dx cos^6 x`

= `3 sin^2 x d/dx (sin x) + 6cos^5 x d/dx (cos x)`

= 3 sin2 x cos x + 6 cos5 x (−sin x)

= 3 sin2 x cos x − 6 cos5 x sin x

= 3 sin x cos x (sin x − 2 cos4 x)

shaalaa.com
  Is there an error in this question or solution?
Chapter 5: Continuity and Differentiability - Exercise 5.9 [Page 191]

APPEARS IN

NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 5 Continuity and Differentiability
Exercise 5.9 | Q 2 | Page 191

RELATED QUESTIONS

Differentiate the function with respect to x.

sin (x2 + 5)


Differentiate the function with respect to x.

cos (sin x)


Differentiate the function with respect to x.

`sec(tan (sqrtx))`


Differentiate the function with respect to x.

`(sin (ax + b))/cos (cx + d)`


Differentiate the function with respect to x. 

cos x3 . sin2 (x5)


Differentiate the function with respect to x. 

`2sqrt(cot(x^2))`


Prove that the function f given by f(x) = |x − 1|, x ∈ R is not differentiable at x = 1.


Differentiate the function with respect to x:

(3x2 – 9x + 5)9


Differentiate the function with respect to x:

`sin^(–1)(xsqrtx), 0 ≤ x ≤ 1`


Differentiate the function with respect to x:

`x^(x^2 -3) + (x -3)^(x^2)`, for x > 3


Find `dy/dx`, if y = 12 (1 – cos t), x = 10 (t – sin t), `-pi/2 < t < pi/2`.


If (x – a)2 + (y – b)2 = c2, for some c > 0, prove that `[1+ (dy/dx)^2]^(3/2)/((d^2y)/dx^2)` is a constant independent of a and b.


Discuss the continuity and differentiability of the 

\[f\left( x \right) = \left| x \right| + \left| x - 1 \right| \text{in the interval} \left( - 1, 2 \right)\]

If sin y = xsin(a + y) prove that `(dy)/(dx) = sin^2(a + y)/sin a`


`"If y" = (sec^-1 "x")^2 , "x" > 0  "show that"  "x"^2 ("x"^2 - 1) (d^2"y")/(d"x"^2) + (2"x"^3 - "x") (d"y")/(d"x") - 2 = 0`


Let f(x) = x|x|, for all x ∈ R. Discuss the derivability of f(x) at x = 0


Differentiate `tan^-1 (sqrt(1 - x^2)/x)` with respect to`cos^-1(2xsqrt(1 - x^2))`, where `x ∈ (1/sqrt(2), 1)`


If u = `sin^-1 ((2x)/(1 + x^2))` and v = `tan^-1 ((2x)/(1 - x^2))`, then `"du"/"dv"` is ______.


COLUMN-I COLUMN-II
(A) If a function
f(x) = `{((sin3x)/x, "if"  x = 0),("k"/2",",  "if"  x = 0):}`
is continuous at x = 0, then k is equal to
(a) |x|
(B) Every continuous function is differentiable (b) True
(C) An example of a function which is continuous
everywhere but not differentiable at exactly one point
(c) 6
(D) The identity function i.e. f (x) = x ∀ ∈x R
is a continuous function
(d) False

|sinx| is a differentiable function for every value of x.


Show that the function f(x) = |sin x + cos x| is continuous at x = π.


sinmx . cosnx


(x + 1)2(x + 2)3(x + 3)4


`tan^-1 (sqrt((1 - cosx)/(1 + cosx))), - pi/4 < x < pi/4`


`tan^-1 (secx + tanx), - pi/2 < x < pi/2`


`sec^-1 (1/(4x^3 - 3x)), 0 < x < 1/sqrt(2)`


`tan^-1 ((sqrt(1 + x^2) + sqrt(1 - x^2))/(sqrt(1 + x^2) - sqrt(1 - x^2))), -1 < x < 1, x ≠ 0`


If xm . yn = (x + y)m+n, prove that `("d"^2"y")/("dx"^2)` = 0


The differential coefficient of `"tan"^-1 ((sqrt(1 + "x") - sqrt (1 - "x"))/(sqrt (1+ "x") + sqrt (1 - "x")))` is ____________.


A function is said to be continuous for x ∈ R, if ____________.


The rate of increase of bacteria in a certain culture is proportional to the number present. If it doubles in 5 hours then in 25 hours, its number would be


`d/(dx)[sin^-1(xsqrt(1 - x) - sqrt(x)sqrt(1 - x^2))]` is equal to


Let c, k ∈ R. If f(x) = (c + 1)x2 + (1 – c2)x + 2k and f(x + y) = f(x) + f(y) – xy, for all x, y ∈ R, then the value of |2(f(1) + f(2) + f(3) + ... + f(20))| is equal to ______.


If f(x) = `{{:(ax + b; 0 < x ≤ 1),(2x^2 - x; 1 < x < 2):}` is a differentiable function in (0, 2), then find the values of a and b.


Prove that the greatest integer function defined by f(x) = [x], 0 < x < 3 is not differentiable at x = 1 and x = 2.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×