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Question
Differentiate the function with respect to x:
sin3 x + cos6 x
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Solution
Let, y = sin3 x + cos6 x
On differentiating with respect to x,
`dy/dx = d/dx sin^3 x + d/dx cos^6 x`
= `3 sin^2 x d/dx (sin x) + 6cos^5 x d/dx (cos x)`
= 3 sin2 x cos x + 6 cos5 x (−sin x)
= 3 sin2 x cos x − 6 cos5 x sin x
= 3 sin x cos x (sin x − 2 cos4 x)
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