मराठी

Differentiate the function with respect to x: sin3 x + cos6 x

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प्रश्न

Differentiate the function with respect to x:

sin3 x + cos6 x

बेरीज
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उत्तर

Let, y = sin3 x + cos6 x

On differentiating with respect to x,

`dy/dx = d/dx sin^3 x + d/dx cos^6 x`

= `3 sin^2 x d/dx (sin x) + 6cos^5 x d/dx (cos x)`

= 3 sin2 x cos x + 6 cos5 x (−sin x)

= 3 sin2 x cos x − 6 cos5 x sin x

= 3 sin x cos x (sin x − 2 cos4 x)

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पाठ 5: Continuity and Differentiability - Exercise 5.9 [पृष्ठ १९१]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 5 Continuity and Differentiability
Exercise 5.9 | Q 2 | पृष्ठ १९१

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