मराठी

Differentiate the function with respect to x. sec⁡(tan⁡(√𝑥))

Advertisements
Advertisements

प्रश्न

Differentiate the function with respect to x.

`sec(tan (sqrtx))`

बेरीज
Advertisements

उत्तर

Let, y = `sec(tan (sqrtx))`

Differentiating both sides with respect to x,

`dy/dx = d/dx sec [tan (sqrtx)]`

= `sec (tan sqrtx) tan (tan sqrtx) d/dx tan sqrtx`

= `sec (tan sqrtx) tan (tan sqrtx) sec^2 sqrtx d/dx (sqrtx)`

= `sec (tan sqrtx) tan (tan sqrtx) sec^2 sqrtx * 1/2 x^(1/2-1)`

= `sec (tan sqrtx) tan (tan sqrtx) sec^2 sqrtx * 1/(2sqrtx)`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Continuity and Differentiability - Exercise 5.2 [पृष्ठ १६६]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
पाठ 5 Continuity and Differentiability
Exercise 5.2 | Q 4 | पृष्ठ १६६

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Differentiate the function with respect to x.

sin (x2 + 5)


Prove that the function f given by f(x) = |x − 1|, x ∈ R is not differentiable at x = 1.


Differentiate the function with respect to x:

`(5x)^(3cos 2x)`


Find `dy/dx`, if y = 12 (1 – cos t), x = 10 (t – sin t), `-pi/2 < t < pi/2`.


If f(x) = |x|3, show that f"(x) exists for all real x and find it.


Does there exist a function which is continuos everywhere but not differentiable at exactly two points? Justify your answer?


Discuss the continuity and differentiability of the 

\[f\left( x \right) = \left| x \right| + \left| x - 1 \right| \text{in the interval} \left( - 1, 2 \right)\]

`"If y" = (sec^-1 "x")^2 , "x" > 0  "show that"  "x"^2 ("x"^2 - 1) (d^2"y")/(d"x"^2) + (2"x"^3 - "x") (d"y")/(d"x") - 2 = 0`


If f(x) = x + 1, find `d/dx (fof) (x)`


Let f(x) = x|x|, for all x ∈ R. Discuss the derivability of f(x) at x = 0


If y = tanx + secx, prove that `("d"^2y)/("d"x^2) = cosx/(1 - sinx)^2`


Differential coefficient of sec (tan–1x) w.r.t. x is ______.


If u = `sin^-1 ((2x)/(1 + x^2))` and v = `tan^-1 ((2x)/(1 - x^2))`, then `"du"/"dv"` is ______.


|sinx| is a differentiable function for every value of x.


`sin sqrt(x) + cos^2 sqrt(x)`


sinn (ax2 + bx + c)


`cos(tan sqrt(x + 1))`


`sin^-1  1/sqrt(x + 1)`


`cos^-1 ((sinx + cosx)/sqrt(2)), (-pi)/4 < x < pi/4`


`tan^-1 (sqrt((1 - cosx)/(1 + cosx))), - pi/4 < x < pi/4`


`tan^-1 (secx + tanx), - pi/2 < x < pi/2`


`tan^-1 (("a"cosx - "b"sinx)/("b"cosx - "a"sinx)), - pi/2 < x < pi/2` and `"a"/"b" tan x > -1`


`tan^-1 ((3"a"^2x - x^3)/("a"^3 - 3"a"x^2)), (-1)/sqrt(3) < x/"a" < 1/sqrt(3)`


`tan^-1 ((sqrt(1 + x^2) + sqrt(1 - x^2))/(sqrt(1 + x^2) - sqrt(1 - x^2))), -1 < x < 1, x ≠ 0`


For the curve `sqrt(x) + sqrt(y)` = 1, `"dy"/"dx"` at `(1/4, 1/4)` is ______.


If k be an integer, then `lim_("x" -> "k") ("x" - ["x"])` ____________.


If sin y = x sin (a + y), then value of dy/dx is


If `ysqrt(1 - x^2) + xsqrt(1 - y^2)` = 1, then prove that `(dy)/(dx) = - sqrt((1 - y^2)/(1 - x^2))`


A particle is moving on a line, where its position S in meters is a function of time t in seconds given by S = t3 + at2 + bt + c where a, b, c are constant. It is known that at t = 1 seconds, the position of the particle is given by S = 7 m. Velocity is 7 m/s and acceleration is 12 m/s2. The values of a, b, c are ______.


Let S = {t ∈ R : f(x) = |x – π| (e|x| – 1)sin |x| is not differentiable at t}. Then the set S is equal to ______.


If f(x) = | cos x |, then `f((3π)/4)` is ______.


The set of all points where the function f(x) = x + |x| is differentiable, is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×