मराठी

Sinn (ax2 + bx + c)

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प्रश्न

sinn (ax2 + bx + c)

बेरीज
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उत्तर

Let y = sinn (ax2 + bx + c)

Differentiating both sides w.r.t. x

`"dy"/"dx" = "d"/"dx" sin^"n" ("a"x^2 + "b"x + "c")`

= `"n" * sin^("n" - 1) ("a"x^2 + "b"x + "c") * "d"/"dx" sin("a"x^2 + "b"x + "c")`

= `"n" * sin^("n" - 1) ("a"x^2 + "b"x + "c") * cos("a"x^2 + "b"x + "c") * "d"/"dx" ("a"x^2 + "b"x + "c")`

= `"n" * sin^("n" - 1) ("a"x^2 + "b"x + "c") * cos("a"x^2 + "b"x + "c") * (2"a"x + "b")`

Hence, `"dy"/"dx" = "n"  (2"a"x + "b") * sin^("n" - 1)("a"x^2 + "b"x + "c")*cos("a"x^2 + "b"x + "c")`

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पाठ 5: Continuity And Differentiability - Exercise [पृष्ठ १०९]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
पाठ 5 Continuity And Differentiability
Exercise | Q 30 | पृष्ठ १०९

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